zrd Class Microprocessor Dr. Mohanad A. Shehab Homework (3): Logical Instructions 1) For register AH • Set bits b0, b3 • Invert bits bl, b6, b7 • Reset bit b2, • don't affect other bits
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- H.W :- 1) A four logic-signal A,B,C,D are being used to represent a 4-bit binary number with A as the LSB and D as the MSB. The binary inputs are fed to a logic circuit that produces a logic 1 (HIGH) output only when the binary number is greater than 01102-610. Design this circuit. 2) repeat problem 1 for the output will be 0 (LOW) when the binary input is less than 01112-710- Saleem Lateef(c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).USE DIGITAL LOGIC AND DESIGN Part 1: In Figure_4; we have 4-bit Comparator using 2-bit Comparators block. You have to satisfy given condition by applying all data on figure 4. At the end, given condition should produce HIGH output and other two should be LOW. A3 A2 A1 A0 = 1101 and B3 B2 B1 B0 = 1110 Figure_4 Part 2: The serial data-input waveform (Data in) and data-select inputs (S0 and S1) are shown in Figure_5. Determine the data-output waveforms from D0 through D3. Figure_5 Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. Figure_6 Part 4: The data-input and…
- 1. Assume that the registers are 8-bit wide. Consider the following code: MOV R1, #4A MOV R2, #40 ADD R3, R1, R2 a) What will be the 8-bit result in Register R3 (in hex)? b) What is the 8-bit result in Register R3 (as unsigned decimal)? c) What is the 8-bit result in Register R3 (as signed decimal)? d) What will be the value of the carry (C) bit?Adocs.google.com is a logic switch that select information from one of the input line and directs it to a single line Encoder Decoder Adder Multiplexer Binary to octal can be implemented used 3-8 De-Multiplexer Multiplexer Decoder Encoder System base 12 include numbers from ... to .... 1-B 1-C 1-12 1-11 ۹:۰۳ FQuestion iii please help......
- 1. In the following diagram, you have the architecture of the Intel 8086 questions: Briefly following microprocessor. [CO1/UNDERSTAND] To memory and Input/ Output answer the BIU 6. 5. 4 3. 2 Σ 6-Byte pre-fetch PA Seg X 10H + offset CS SS DS ES IP queue Control Unit EU AH AL AX General BH BL -BX -CX -DX Purpose Registers CH CL DH ALU DL SP ВР SI DI Operands Flags Block Diagram of 8086 Microprocessor Electronics Desk a)Why is the architecture of 8086 divided into two parts? How can the two units enhance the total system performance? b)How many registers are there inside Intel 8086? What is the purpose of segment registers and general-purpose registers? Mention the names also.QUESTION: DERIVE EXPRESSION VO IN TERMS OF THE INPUT VOLTACES V. HENCE SO THAT 4-BIT V₁ पैर AN A VALUE of LOGICO OUTPUT EA X₁₂ DELIVE THE INPUT VOLTACES V₁ V₁ AND VALY ES FOR THE CIRCUIT COMPONENTS THE CIRCUIT MAY BE USED AS A DIGITAL TO ANALOG CONFERTER. Assums 10ke For RE, LOGIC "'I' IS SVOUT] O VOLTS AND Full SCALE ANALOG IS IS VOLTS, STATE ANY ASSUMPTIONS MADE. Rf (₂ Ro FOR THE OUTPUT VOLTAGE IS SUMMING AMPLIFIER. VoQ3/(A) False OR True 1- A0-0 and BHE-1 are used as low bank-select signal: 2-AX is 2234 H after executing the following instruction: AAS. If AX-2234H. 3-IP register holds the offset address of the next instruction to be executed. 4- The XLAT instruction in 8086 assembly language is used to perform arithmetic operations between two memory operands. 5- Bus interface unit is responsible form
- What is the value for the 32-bit register EAX after executing the mnemonic opcode/operand instruction MOVZX? (This mnemonic opcode/operand instruction converts 8-bits to 32-bits) MOV EAX, 0 MOV AX, 0X54C9BF5 MOVZX EAX, AX EAX= 004C9BF5 а. EAX= 000C9BF5 b. EAX= 000000F5 EAX= 00009BF5 O d.Please help me, solve this question.QUESTION i please help........