Zland 22 are a linear pair, and 22 and 23 are vertical angles. m21 = (5y – 8)° and m22 = (12 + 6y). What is mZ3? O 16° O 72° O 108°

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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### 8.03 Semester Test: Grade 8 Semester B Test - Par

**Problem Statement:**

\(\angle 1\) and \(\angle 2\) are a linear pair, and \(\angle 2\) and \(\angle 3\) are vertical angles. \(m\angle 1 = (5y - 8)^\circ\) and \(m\angle 2 = (12 + 6y)^\circ\).

What is \(m\angle 3\)?
- 16°
- 72°
- 108°
- 132°

**Explanation:**

The given problem involves understanding the relationships between linear pairs and vertical angles to solve for the measure of \(\angle 3\).

1. Since \(\angle 1\) and \(\angle 2\) are a linear pair, their measures add up to 180°:
   \[
   m\angle 1 + m\angle 2 = 180^\circ
   \]
   Substitute the given expressions:
   \[
   (5y - 8) + (12 + 6y) = 180
   \]
   Simplify and solve for \(y\):
   \[
   5y - 8 + 12 + 6y = 180
   \]
   \[
   11y + 4 = 180
   \]
   \[
   11y = 176
   \]
   \[
   y = 16
   \]

2. Substitute \(y = 16\) back into the expression for \(m\angle 2\):
   \[
   m\angle 2 = 12 + 6(16)
   \]
   \[
   m\angle 2 = 12 + 96
   \]
   \[
   m\angle 2 = 108^\circ
   \]
   
3. Since \(\angle 2\) and \(\angle 3\) are vertical angles, they are equal:
   \[
   m\angle 3 = m\angle 2 = 108^\circ
   \]

Thus, the correct answer is:

**108°**

**Answer Choices Interaction:**

On the webpage, the answer choices are presented as selectable options:

- \( \quad \) 16°
- \( \quad \) 72°
Transcribed Image Text:### 8.03 Semester Test: Grade 8 Semester B Test - Par **Problem Statement:** \(\angle 1\) and \(\angle 2\) are a linear pair, and \(\angle 2\) and \(\angle 3\) are vertical angles. \(m\angle 1 = (5y - 8)^\circ\) and \(m\angle 2 = (12 + 6y)^\circ\). What is \(m\angle 3\)? - 16° - 72° - 108° - 132° **Explanation:** The given problem involves understanding the relationships between linear pairs and vertical angles to solve for the measure of \(\angle 3\). 1. Since \(\angle 1\) and \(\angle 2\) are a linear pair, their measures add up to 180°: \[ m\angle 1 + m\angle 2 = 180^\circ \] Substitute the given expressions: \[ (5y - 8) + (12 + 6y) = 180 \] Simplify and solve for \(y\): \[ 5y - 8 + 12 + 6y = 180 \] \[ 11y + 4 = 180 \] \[ 11y = 176 \] \[ y = 16 \] 2. Substitute \(y = 16\) back into the expression for \(m\angle 2\): \[ m\angle 2 = 12 + 6(16) \] \[ m\angle 2 = 12 + 96 \] \[ m\angle 2 = 108^\circ \] 3. Since \(\angle 2\) and \(\angle 3\) are vertical angles, they are equal: \[ m\angle 3 = m\angle 2 = 108^\circ \] Thus, the correct answer is: **108°** **Answer Choices Interaction:** On the webpage, the answer choices are presented as selectable options: - \( \quad \) 16° - \( \quad \) 72°
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