Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) + 2 HCl(aq) - · ZnCl₂(aq) + H₂(g) How many milliliters of 2.50 M HCl(aq) are required to react with 4.85 g Zn(s)? volume: mL

Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) + 2 HCl(aq) - · ZnCl₂(aq) + H₂(g) How many milliliters of 2.50 M HCl(aq) are required to react with 4.85 g Zn(s)? volume: mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

**Reaction of Zinc with Hydrochloric Acid**

Zinc reacts with hydrochloric acid according to the following reaction equation:

\[ \text{Zn(s)} + 2 \text{HCl(aq)} \rightarrow \text{ZnCl}_2\text{(aq)} + \text{H}_2\text{(g)} \]

**Question:**
How many milliliters of 2.50 M HCl(aq) are required to react with 4.85 g of Zn(s)?

**Solution:**
To find the volume of HCl needed, calculate the number of moles of zinc and then use stoichiometry to determine the volume of HCl solution required.

\[ \text{Volume:} \, \_\_\_\_\_\_\_\_\_ \, \text{mL} \]

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