Зф Source Z Line Зф Load Three-phase System Data: Sources: Ean = 12020° v; Epn = 150 – 143.13° v; Een = 90490° v (grounded neutral) Zan = Zbn = Zen = 0.1 + j1.5 N %3D %3D Line Impedances: Zline a = 1+ j2 N; Ziine b = 1 – j2 N; Zine c = 0 + j2.2361 N Load Impedances: Load 2c: Zan = 12 + j9 N; Zbn = 12 – j9 N; Zen = 15 + j0 N (grounded neutral) %3D Find: Under Unbalanced Condition With Faults: a. Load Line Currents (Ia, Ip, I); b. Load Line Voltages (Vab, Vpc, Vca); c. Load Power Profile (Pr, Qr, ST,pfr); d. The Fault Current (If)

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Solve the following Three-Phase Unbalanced

Зф Source
ZLine
Зф Load
Three-phase System Data:
Sources:
Ean = 12020° v; Epn = 1502 – 143.13° v; Een = 90290° v (grounded neutral)
Zan = Zbn = Zcn = 0.1 + j1.5 N
Line Impedances:
Zline a = 1+ j2 N; Zine b = 1 – j2 N; Zline c = 0 + j2.2361 N
Load Impedances:
Load 2c: Zan = 12 + j9 N; Zpn = 12 – j9 N; Zen
= 15 + j0 N (grounded neutral)
%3D
Find:
Under Unbalanced Condition With Faults:
a. Load Line Currents (Ia, Ip,Ic);
b. Load Line Voltages (Vab, Vbc,Vca);
c. Load Power Profile (Pr, Qr, Sr,pfr);
d. The Fault Current (If)
Transcribed Image Text:Зф Source ZLine Зф Load Three-phase System Data: Sources: Ean = 12020° v; Epn = 1502 – 143.13° v; Een = 90290° v (grounded neutral) Zan = Zbn = Zcn = 0.1 + j1.5 N Line Impedances: Zline a = 1+ j2 N; Zine b = 1 – j2 N; Zline c = 0 + j2.2361 N Load Impedances: Load 2c: Zan = 12 + j9 N; Zpn = 12 – j9 N; Zen = 15 + j0 N (grounded neutral) %3D Find: Under Unbalanced Condition With Faults: a. Load Line Currents (Ia, Ip,Ic); b. Load Line Voltages (Vab, Vbc,Vca); c. Load Power Profile (Pr, Qr, Sr,pfr); d. The Fault Current (If)
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