Zero of -3 having multiplicity 3 and f(3) = 36 x = -3√ x = 3₁ x= 3√√x=3 +3)(xx-3)(x-3)(x-3)(x-3) m(x+3)(x-3)(x-3)(x-3)=36 (1263-3 (²-3)(3-3)=36 m = 36 m=

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