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Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Topic Video
Question
Title: Analyzing a Right Triangle

### Problem Statement:
Given a right triangle ABC with the following dimensions:
- Side AC = 7 units
- Side BC = 6 units

### Required:
Determine the following:
1. The measure of angle ∠B.
2. The measure of angle ∠A.
3. The length of side AB.

### Diagram:
The diagram depicts a right triangle labelled ABC. The right angle is at vertex C. The lengths of sides AC and BC are 7 units and 6 units, respectively.

### Solution:

1. **Calculate the Hypotenuse (AB):**

    Using the Pythagorean theorem for right-angled triangles:
    
    \[
    AB^2 = AC^2 + BC^2
    \]

    Substituting the known values:

    \[
    AB^2 = 7^2 + 6^2 \\
    AB^2 = 49 + 36 \\
    AB^2 = 85 \\
    AB = \sqrt{85} \\
    AB \approx 9.22 \text{ units} \\
    \]

2. **Measure of Angle ∠B:**

    Since we know the values of the opposite side (BC) and the adjacent side (AC), we can use the tangent function:

    \[
    \tan(B) = \frac{\text{opposite}}{\text{adjacent}} \\
    \tan(B) = \frac{6}{7}
    \]

    Using an inverse tangent function (arctan) to find the measure of angle B:

    \[
    B = \arctan\left(\frac{6}{7}\right) \\
    B \approx 40.60^\circ
    \]

3. **Measure of Angle ∠A:**

    Since the sum of the angles in any triangle is 180 degrees and one angle is 90 degrees:

    \[
    A + B = 90^\circ \\
    A = 90^\circ - B \\
    A = 90^\circ - 40.60^\circ \\
    A \approx 49.40^\circ
    \]

### Conclusion:
- ∠B ≈ 40.60°
- ∠A ≈ 49.40°
- The length of side AB ≈ 9.22 units.
Transcribed Image Text:Title: Analyzing a Right Triangle ### Problem Statement: Given a right triangle ABC with the following dimensions: - Side AC = 7 units - Side BC = 6 units ### Required: Determine the following: 1. The measure of angle ∠B. 2. The measure of angle ∠A. 3. The length of side AB. ### Diagram: The diagram depicts a right triangle labelled ABC. The right angle is at vertex C. The lengths of sides AC and BC are 7 units and 6 units, respectively. ### Solution: 1. **Calculate the Hypotenuse (AB):** Using the Pythagorean theorem for right-angled triangles: \[ AB^2 = AC^2 + BC^2 \] Substituting the known values: \[ AB^2 = 7^2 + 6^2 \\ AB^2 = 49 + 36 \\ AB^2 = 85 \\ AB = \sqrt{85} \\ AB \approx 9.22 \text{ units} \\ \] 2. **Measure of Angle ∠B:** Since we know the values of the opposite side (BC) and the adjacent side (AC), we can use the tangent function: \[ \tan(B) = \frac{\text{opposite}}{\text{adjacent}} \\ \tan(B) = \frac{6}{7} \] Using an inverse tangent function (arctan) to find the measure of angle B: \[ B = \arctan\left(\frac{6}{7}\right) \\ B \approx 40.60^\circ \] 3. **Measure of Angle ∠A:** Since the sum of the angles in any triangle is 180 degrees and one angle is 90 degrees: \[ A + B = 90^\circ \\ A = 90^\circ - B \\ A = 90^\circ - 40.60^\circ \\ A \approx 49.40^\circ \] ### Conclusion: - ∠B ≈ 40.60° - ∠A ≈ 49.40° - The length of side AB ≈ 9.22 units.
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