z²+2z-5 4.78. (a) If C is the circle |z| = R, show that lim R-00 (2²+4)(z² +2z+2) -dz = 0 (b) Use the result of (a) to deduce that if C₁ is the circle |z2| = 5, then z²+2z-5 (z²+4)(z²+2z+2) (c) Is the result in (b) true if C₁ is the circle |z+ 11 = 2? Explain. -dz = 0

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