Z10 Z11 = Z12 = Z13 Z14 = Z15 = Z16 Z17 = Z18 = Z19 (iii) Consequently, the required representation of e3.24 in the FPA6 is
Z10 Z11 = Z12 = Z13 Z14 = Z15 = Z16 Z17 = Z18 = Z19 (iii) Consequently, the required representation of e3.24 in the FPA6 is
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Z10
Z11
Z12
Z13
Z14 =
Z15
Z16
=
Z17 =
Z18
=
Z19 =
(iii) Consequently, the required representation of e3.24 in the FPA is

Transcribed Image Text:(Taylor Series/Polynomials, Exponential Function). (i) Find the representation of e³.24 in the FPA by generating a suitable
number of terms of the sequence (Zn) recursively defined by Zo
= 1 and
Zn = Zn-13.24"/n!,
where n> 1 is a natural number. As we did during the lectures, first try to estimate the number of steps to obtain the
representation in question, and then carry out the calculations till the condition
Zk = Zk-1
3.24
will become true at some step k. The number Zk will then be the required representation e
(ii) Show your work by entering the terms Zn, suitable 6-digit floating-point numbers, you have calculated in (i) in the input
fields below; if a particular input field is not necessary, please enter an asterisk * in it:
Zo
Z₁
Z3
N
Z₂ =
Z4
Z6
Z7
Z8
=
Z5 =
Z9
||
N
=
||
||
||
in the FPA6.
||
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