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z+1 Let f(z) = Then (z-2i1z-41) (1) the residues at z = 2i and z = 4i are Resf(2i)= Resf(4i)= (2) The integral on the contour Iz| = 3 is equal to Se z+1 dz= (z-2ijz-4i) (3) The integral on the contour Iz| = 6 is equal to z+1 Sc dz= (z-2ilz-4i) (4) The integral on the contour Iz| = 1 is equal to 3+1 dz= (z-2ijz-4i)

z+1 Let f(z) = Then (z-2i1z-41) (1) the residues at z = 2i and z = 4i are Resf(2i)= Resf(4i)= (2) The integral on the contour Iz| = 3 is equal to Se z+1 dz= (z-2ijz-4i) (3) The integral on the contour Iz| = 6 is equal to z+1 Sc dz= (z-2ilz-4i) (4) The integral on the contour Iz| = 1 is equal to 3+1 dz= (z-2ijz-4i)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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z+1 Let f(z) = Then (z-2i1z-41) (1) the residues at z = 2i and z = 4i are Resf(2i)= Resf(4i)= (2) The integral on the contour Iz| = 3 is equal to Se z+1 dz= (z-2ijz-4i) (3) The integral on the contour Iz| = 6 is equal to z+1 Sc dz= (z-2ilz-4i) (4) The integral on the contour Iz| = 1 is equal to +1 dz= (z-2i(z-4i)
Transcribed Image Text:z+1 Let f(z) = Then (z-2i1z-41) (1) the residues at z = 2i and z = 4i are Resf(2i)= Resf(4i)= (2) The integral on the contour Iz| = 3 is equal to Se z+1 dz= (z-2ijz-4i) (3) The integral on the contour Iz| = 6 is equal to z+1 Sc dz= (z-2ilz-4i) (4) The integral on the contour Iz| = 1 is equal to +1 dz= (z-2i(z-4i)
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