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З^1 — 2л2 + 5аз — —17 2x1 + 4x2 – 3x3 = 29 5х1 — 6х2 — 7*3 — 7

З^1 — 2л2 + 5аз — —17 2x1 + 4x2 – 3x3 = 29 5х1 — 6х2 — 7*3 — 7

Intermediate Algebra
Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter8: Roots And Radicals
Section8.8: Use The Complex Number System
Problem 8.159TI: Multiply: (53i)(12i)
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Solve the following set of equations using the matrix inverse method:

3x1 – 2x2 + 5x3 || 201 + 422 — 3х3 — 29 5x1 – 6x2 – 7x3 = 7 -
Transcribed Image Text:3x1 – 2x2 + 5x3 || 201 + 422 — 3х3 — 29 5x1 – 6x2 – 7x3 = 7 -
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