З tan (70)- -1 where 0 is any real number and k is any integer

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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solve the following equations over the specified domain. Your
final answers must be exact and simplified (no approximations).

**Problem Statement:**

b. \(\sqrt{3} \tan(7\theta) = -1\) 

where \(\theta\) is any real number and \(k\) is any integer. 

**Discussion:**

The given equation involves trigonometric functions and seeks to find values for \(\theta\) that satisfy the equation for any integer \(k\). The challenge is to solve it using trigonometric identities and properties of the tangent function. 

**Approach:**

1. **Isolate the Tangent Function:**

   \[
   \tan(7\theta) = -\frac{1}{\sqrt{3}}
   \]

2. **Consider the Special Angles:**

   Recognize that \(\tan(\theta) = -\frac{1}{\sqrt{3}}\) corresponds to angles where the tangent function has this specific value. Therefore, consider the angles in the unit circle where this occurs, keeping in mind the periodic nature of the tangent function:

   \[
   7\theta = \left\{-\frac{\pi}{6} + k\pi\right\}
   \]

3. **Solve for \(\theta\):**

   Divide by 7 to isolate \(\theta\):

   \[
   \theta = \left\{-\frac{\pi}{42} + \frac{k\pi}{7}\right\}
   \]

Hence, the general solution involves considering all real numbers \(\theta\) and integers \(k\).
Transcribed Image Text:**Problem Statement:** b. \(\sqrt{3} \tan(7\theta) = -1\) where \(\theta\) is any real number and \(k\) is any integer. **Discussion:** The given equation involves trigonometric functions and seeks to find values for \(\theta\) that satisfy the equation for any integer \(k\). The challenge is to solve it using trigonometric identities and properties of the tangent function. **Approach:** 1. **Isolate the Tangent Function:** \[ \tan(7\theta) = -\frac{1}{\sqrt{3}} \] 2. **Consider the Special Angles:** Recognize that \(\tan(\theta) = -\frac{1}{\sqrt{3}}\) corresponds to angles where the tangent function has this specific value. Therefore, consider the angles in the unit circle where this occurs, keeping in mind the periodic nature of the tangent function: \[ 7\theta = \left\{-\frac{\pi}{6} + k\pi\right\} \] 3. **Solve for \(\theta\):** Divide by 7 to isolate \(\theta\): \[ \theta = \left\{-\frac{\pi}{42} + \frac{k\pi}{7}\right\} \] Hence, the general solution involves considering all real numbers \(\theta\) and integers \(k\).
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