z is a standard normal random variable. The P(-1.96 ≤z S-1.4) equals O a. 0.475 Ob. 0.0558 O c. 0.4192 O d. 0.8942
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- Assume that the random variable X is normally distributed when mean u= 80 and the standard deviation o=15 compute the probability P( X >92) A. 0.2420 B. 0.1977 C. 0.7881 D. 0.2119Let xbe a Geometric random variable with p% = 0.6. Find the mgf at zero MO) O 0.5 O 0.4 NoneLet X denote the mean of a random sample size n from distribution that has mean U and variance o = 10. Find the sample size n, so that the probability is approximately =0.954 %3D that the random interval X -5,X+5 | contains U is Select one: a. n=100 b. n= 40 C. n = 80 d. n = 160
- G and HLet x be a random variable that represents the batting average of a professional baseball player. Let y be a random variable that represents the percentage of strikeouts of a professional baseball player. A random sample of n = 6 professional baseball players gave the following information. x 0.318 0.272 0.340 0.248 0.367 0.269 y 3.4 8.0 4.0 8.6 3.1 11.1 Σx = 1.814, Σy = 38.2, Σx2 = 0.559262, Σy2 = 298.34, Σxy = 10.8736, and r ≈ -0.874. (d) Find the predicted percentage of strikeouts for a player with an x = 0.35 batting average. (Use 2 decimal places.)%(e) Find a 95% confidence interval for y when x = 0.35. (Use 2 decimal places.) lower limit % upper limit % (f) Use a 1% level of significance to test the claim that β ≠ 0. (Use 2 decimal places.) t critical t ±Please help me answer all parts
- Let Z be a standard normal random variable. Determine the value. P(Z is less than or equal to c)=0.8621 Carry intermediate computations to at least 4 decimal places. Round answer to 2 decimal places.Z is a standard normal random variableLet x be a random variable that represents the batting average of a professional baseball player. Let y be a random variable that represents the percentage of strikeouts of a professional baseball player. A random sample of n = 6 professional baseball players gave the following information. x 0.318 0.272 0.340 0.248 0.367 0.269 y 3.4 8.0 4.0 8.6 3.1 11.1 Σx = 1.814, Σy = 38.2, Σx2 = 0.559262, Σy2 = 298.34, Σxy = 10.8736, and r ≈ -0.874. (e) Find a 95% confidence interval for y when x = 0.35. (Use 2 decimal places.) lower limit % upper limit (g) Find a 95% confidence interval for β and interpret its meaning. (Use 2 decimal places.) lower limit upper limit
- Let Z be a standard normal variable. Find the value of z if z satisfies P(Z > z) = 0.6331. a) 00.35 b) O-0.3 с) О-034 d) 00.34 e) 00.30 D O None of the above. Question 29 Suppose X is a normal random variable with u = 35 and o = 10. Find P(21.4 < X < 39.7). a) 005586 b) 00.5337 c) O0.5939 d) O0.2323 e) 0 0.2478 f) O None of the above.If z is a standard normal random variable, then P (1.83 < z < 2.38) is:Suppose X is a normal random variable with µ = 30 and o = 5. Find the following: a. P(X 25)
