z" +7.84x = 5 cos(3t), (0) = r'(0) = 0

Q: Find f. f"(x) = cos(x), f(0) = 3, f'(0) = 6, f"(0) = 4

A:

Q: Differentiate. f(0) = 0 cos(0) sin(0)

A:

Q: If H(0) = 0 sin 0, find H'(0) and H"(0). %3D H'(0) =

A:

Q: Find f. f"(x) = cos(x), f(0) = 6, f'(0) = 4, f"(0) = 9 f(x) =

A: We can find the value of f(x) as below.

Q: Find f. f "(x) = 7 + cos(x), f(0) = -1, f(71/2) = 0 %3D %3D

A:

Q: (10) y = एस COS (5x) ) y' = ?

A: By applying the product rule for the differentiation.

Q: Given f"(x) =| 16 sin(4x) and Find f

A:

Q: Find f. f"(0) = sin(0) + cos(0), f(0) = 3, f'(0) = 4 f(0) =

A: Objective is to find f.

Q: If y = -cos(2t), then y(5)= ?

A:

Q: Find y' and y". y=2sin4x-cos(8x-1)

A: Let's find.

Q: find y'. (show all the steps please) cos(xy) = x-y^2

A:

Q: find dy/dxy=x/1+cosx

A: we have to find derivative of f(x)we will use following rule

Q: y" - y' - y = cos(5t) - sin(5t); y(0) = 2 and y'=5

A: Given :y''-y'-y=cos5t-sin5ty(0)=2 and y'(0)=5

Q: If f(x) = 5 sin−¹(x³), find ƒ'(x). 15x² cos(x³) sin(2³)² x3 Find f'(0.4). X

A:

Q: (a) [- 9x2 +x° cos x dx = 3

A: Since you have asked multiple questions in single request  so we  will be answering only first…

Q: y=cos(4x) /cos22x-4sin2x cos2x differentiate?

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Q: If H(0) = 0 cos 0, find H'(0) and H"(0). H'(0) H"(0) %3|

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Q: Using Variation of Parameters 4y''-4=cos-1x

A: Given that, 4y''-4=cos-1x Now let's take, 4y''-4=0 Take m=ddx, 4m2-4y=04m2-4=0m=±1 So the homogenous…

Q: solve for y'. y=sin-1[(ax+b)/(bx+a)]

A: Sin-1x can be written as asin(X)   So we have expression as y=sin-1(ax+b)(bx+a) We have to solve for…

Q: Find f. f"(0) = sin(0) + cos(8), f(0) = 5, f'(0) = 2

A: Given, f"(θ)=sinθ+cosθ f(0)=5 and f'(0)=2

Q: y = π/2 sinx y' =

A:

Q: Find y'. sin t y = 8 + t %3D y' = %3D Find y'. 2 sin 0 + 9 cos 0 y = %3D sin 0 – cos 0 y' = %3D

A:

Q: Find y' and y". y = cos(sin(90)) y' %3D %3D

A: We have to find

Q: let y=[cos(2x-π)]3 Find y' at x=(π/6)

A: Compute the derivative as follows.

Q: Find f. f"(e) = sin(e) + cos(8), f(0) = 2, f(0) = 2 f(e) =

A: Given problem:- f''(θ) = sin(θ) + cos(θ) , f(0) =2 , f'(0) =2  To find:- f(θ)

Q: Find f. f '(x) = cos(x), f(0) = 6, f '(0) = 3, f "(0) = 5

A: Differential equation: f'''(x)=cosx f(0)=6, f'(0)=3 f''(0)=5

Q: cos²od0 1. S sin*0 2. S(e-t + e')²dt

A:

Q: f(x) = cos3(4x-1) Differentiate the equation

A: Given that: f(x)=cos3(4x-1)

Q: 8e cos 2x dx csc(x) sec(x)

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Q: Find f. f(0) = f"(0) = sin(0) + cos(8), cos(8), f(0) = 1, f '(0) = 3

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Q: Find f. f"(8) = sin(0) + cos(8), F(0) = 5, f(0) = 4 F(8) -sin(0) – cos(0) + 5x + 6

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Q: Find dy/dx of the function below. 2x³ + e^(2y) = cos3y

A: 2x3+e2y=cos(3y)Differentiate with respect to…

Q: Find f. f "(0) = sin 0 + cos 0, f(0) = 1, f'(0) = 3

A: