z = -1.61 (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim. OB. O A. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams. 23 O C. Fail to reject Ho. There is sufficient evidence to reject the claim that mean sodium content is no more than 91.6 milligrams. Reject Ho. There is not sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams. 00 O D. Reject Ho. There is sufficient M evidence to reject the claim that mean sodium content is no A more than 916 milligrams.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Question

Answer the question 

**Hypothesis Testing in a Fast Food Scenario: Understanding Sodium Content Claims**

**Problem Statement:**

A fast food restaurant estimates that the mean sodium content in one of its breakfast sandwiches is no more than 916 milligrams. A random sample of 45 breakfast sandwiches has a mean sodium content of 910 milligrams. Assume the population standard deviation is 25 milligrams. At $\alpha = 0.10$, do you have enough evidence to reject the restaurant's claim? Complete parts (a) through (e).

**Step-by-Step Solution:**

**Z-Score Calculation:**
\[ z = \frac{\bar{X} - \mu}{(\sigma / \sqrt{n})} \]

Given:
- Sample mean (\(\bar{X}\)) = 910 mg
- Population mean (\(\mu\)) = 916 mg
- Population standard deviation (\(\sigma\)) = 25 mg
- Sample size (n) = 45
- Significance level (\(\alpha\)) = 0.10

Using the above information, we calculate:
\[ z = \frac{910 - 916}{(25 / \sqrt{45})} \]
\[ z = \frac{-6}{(25 / 6.708)} \]
\[ z = \frac{-6}{3.725} \]
\[ z = -1.61 \]

**Decision Making:**
(d) Decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim.

**Options Provided:**
A) Fail to reject \( H_0 \). There is not sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams.

B) Reject \( H_0 \). There is not sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams.

C) Fail to reject \( H_0 \). There is sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams.

D) Reject \( H_0 \). There is sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams.

**Interpreting the Result:**
Based on the calculated z-score of -1.61 and comparing it against the critical value for \( \alpha = 0.10 \) (approximately ±1.645 for a two-tailed test), the
Transcribed Image Text:**Hypothesis Testing in a Fast Food Scenario: Understanding Sodium Content Claims** **Problem Statement:** A fast food restaurant estimates that the mean sodium content in one of its breakfast sandwiches is no more than 916 milligrams. A random sample of 45 breakfast sandwiches has a mean sodium content of 910 milligrams. Assume the population standard deviation is 25 milligrams. At $\alpha = 0.10$, do you have enough evidence to reject the restaurant's claim? Complete parts (a) through (e). **Step-by-Step Solution:** **Z-Score Calculation:** \[ z = \frac{\bar{X} - \mu}{(\sigma / \sqrt{n})} \] Given: - Sample mean (\(\bar{X}\)) = 910 mg - Population mean (\(\mu\)) = 916 mg - Population standard deviation (\(\sigma\)) = 25 mg - Sample size (n) = 45 - Significance level (\(\alpha\)) = 0.10 Using the above information, we calculate: \[ z = \frac{910 - 916}{(25 / \sqrt{45})} \] \[ z = \frac{-6}{(25 / 6.708)} \] \[ z = \frac{-6}{3.725} \] \[ z = -1.61 \] **Decision Making:** (d) Decide whether to reject or fail to reject the null hypothesis, and (e) interpret the decision in the context of the original claim. **Options Provided:** A) Fail to reject \( H_0 \). There is not sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams. B) Reject \( H_0 \). There is not sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams. C) Fail to reject \( H_0 \). There is sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams. D) Reject \( H_0 \). There is sufficient evidence to reject the claim that mean sodium content is no more than 916 milligrams. **Interpreting the Result:** Based on the calculated z-score of -1.61 and comparing it against the critical value for \( \alpha = 0.10 \) (approximately ±1.645 for a two-tailed test), the
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman