(Z<1.5) (Z> -1.4) P(|Z| < 1.6) (d) P(Z >0.6) (e) P(-1.4 ≤Z≤ 1.5) (Z<1.5)= 0.9332 nd to four decimal places as needed.) (Z>1.4)= 0.9192 nd to four decimal places as needed.) (|Z| < 1.6) = 0.8904 nd to four decimal places as needed.) (Z >0.6)= 0.4514
(Z<1.5) (Z> -1.4) P(|Z| < 1.6) (d) P(Z >0.6) (e) P(-1.4 ≤Z≤ 1.5) (Z<1.5)= 0.9332 nd to four decimal places as needed.) (Z>1.4)= 0.9192 nd to four decimal places as needed.) (|Z| < 1.6) = 0.8904 nd to four decimal places as needed.) (Z >0.6)= 0.4514
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 6E
Related questions
Question
I need help with d and e
![Find these probabilities for a standard normal random variable Z. Be sure to draw a picture to check
your calculations. Use the normal table or software.
(a) P(Z < 1.5)
(b) P(Z > -1.4)
(c) P(|Z| < 1.6)
(d) P(Z >0.6)
(e) P(-1.4≤Z≤1.5)
(a) P(Z < 1.5) = 0.9332
(Round to four decimal places as needed.)
(b) P(Z > -1.4)= 0.9192
(Round to four decimal places as needed.)
(c) P(|Z| < 1.6) = 0.8904
(Round to four decimal places as needed.)
(d) P(|Z| > 0.6) = 0.4514
(Round to four decimal places as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F85e2fdce-e8d6-4d14-abeb-b7fe4de83f35%2Fc9a5cae8-447b-4373-a842-b6624fca3e20%2F2c9q26g_processed.png&w=3840&q=75)
Transcribed Image Text:Find these probabilities for a standard normal random variable Z. Be sure to draw a picture to check
your calculations. Use the normal table or software.
(a) P(Z < 1.5)
(b) P(Z > -1.4)
(c) P(|Z| < 1.6)
(d) P(Z >0.6)
(e) P(-1.4≤Z≤1.5)
(a) P(Z < 1.5) = 0.9332
(Round to four decimal places as needed.)
(b) P(Z > -1.4)= 0.9192
(Round to four decimal places as needed.)
(c) P(|Z| < 1.6) = 0.8904
(Round to four decimal places as needed.)
(d) P(|Z| > 0.6) = 0.4514
(Round to four decimal places as needed.)
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