ReviewYou've decided to protect your house by placing a5.5-m-tall iron lightning rod next to the house. Thetop is sharpened to a point and the bottom is ingood contact with the ground. From your research,you've learned that lightning bolts can carry up to53 kA of current and last up to 50 us.Part AHow much charge is delivered by a lightning bolt with these parameters?Express your answer with the appropriate units.HA?Q =ValueUnitsSubmitRequest AnswerPart BYou don't want the potential difference between the top and bottom of the lightning rod to exceed 130 V. Whatminimum diameter must the rod haveExpress your answer with the appropriate units.dmin =ValueUnitsSuhmitRequest Answer

Given, Rod length, L=5.5m Time, t=50×10-6s Current, I=53×103A Part A, The charge, I=Q∆tQ=I.∆tQ=53×103×50×10-6Q=2.65C Hence, 2.65C charge is delivered by lighting rod. Part B, Voltage, V=130V Resistance, R=VIR=13053×103R=2.45×10-3Ω The resistivity of iron, ρ=9.71×10-8Ωm Let the dmin be the diameter of the rod. According to ohm's law, the resistance is given by, R=ρLA2.45×10-3=9.71×10-8×5.5πdmin24dmin=0.0295mdmin=2.95cm Hence, 2.95cm is minimum diameter of the rod.

Answered: You've decided to protect your house by…