Your team of test engineers is to release the parking brake so an 752.0-kg car will roll down a very long 5.9 percent grade in preparation for a crash test at the bottom of the incline. (On a 5.9 percent grade the change in altitude is 5.9 percent of the horizontal distance traveled.) The total resistive force (air drag plus rolling friction) for this car has been previously established to be Fa = 100 N + (1.2 N · s2/m2)v2, where v is the speed of the car. What is the terminal speed for the car rolling down this grade? m/s

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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Your team of test engineers is to release the parking brake so an 752.0-kg car will roll down a very long 5.9 percent grade in preparation for a crash test at the bottom of
the incline. (On a 5.9 percent grade the change in altitude is 5.9 percent of the horizontal distance traveled.) The total resistive force (air drag plus rolling friction) for this
car has been previously established to be Fg = 100 N + (1.2 N · s2/m2)v2, where v is the speed of the car. What is the terminal speed for the car rolling down this grade?
m/s
еВook
Transcribed Image Text:Your team of test engineers is to release the parking brake so an 752.0-kg car will roll down a very long 5.9 percent grade in preparation for a crash test at the bottom of the incline. (On a 5.9 percent grade the change in altitude is 5.9 percent of the horizontal distance traveled.) The total resistive force (air drag plus rolling friction) for this car has been previously established to be Fg = 100 N + (1.2 N · s2/m2)v2, where v is the speed of the car. What is the terminal speed for the car rolling down this grade? m/s еВook
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