Your friend says you can’t use the equation Δx=v0Δt + 1/2a(Δt)2 to find the horizontal displacement of a horizontal projectile with a constant velocity because you don’t know the acceleration in the horizontal direction. Is your friend correct? Why or why not? My friend is incorrect. If the velocity is constant, then the horizontal acceleration is zero. My friend is incorrect. The horizontal acceleration is the same as horizontal velocity. My friend is incorrect. The acceleration is always −9.8 m/s2. My friend is correct. A different equation must be used to find Δx
Your friend says you can’t use the equation Δx=v0Δt + 1/2a(Δt)2 to find the horizontal displacement of a horizontal projectile with a constant velocity because you don’t know the acceleration in the horizontal direction. Is your friend correct? Why or why not? My friend is incorrect. If the velocity is constant, then the horizontal acceleration is zero. My friend is incorrect. The horizontal acceleration is the same as horizontal velocity. My friend is incorrect. The acceleration is always −9.8 m/s2. My friend is correct. A different equation must be used to find Δx
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Your friend says you can’t use the equation Δx=v0Δt + 1/2a(Δt)2 to find the horizontal displacement of a horizontal projectile with a constant velocity because you don’t know the acceleration in the horizontal direction. Is your friend correct? Why or why not?
- My friend is incorrect. If the velocity is constant, then the horizontal acceleration is zero.
- My friend is incorrect. The horizontal acceleration is the same as horizontal velocity.
- My friend is incorrect. The acceleration is always −9.8 m/s2.
- My friend is correct. A different equation must be used to find Δx
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