Your company has instituted a new physical fitness test. Drawing upon experience from similar companies, you believe that test scores will be normally distributed with mean 48.8 and standard deviation 8.5. You take the test and score a 79. Before estimating the probability of observing a score of 79 or less, you need to convert 79 into the "Z" value so you can use a standard normal distribution. Report Z(X = 79) to one decimal point, note this is the calculated z score not the associated probability.

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