Your classmate wrote a simple function with two optional arguments: X which defaults to the string “a” and Y, which defaults to the empty list. It concatenates its first argument to itself and then appends that to the end of its second argument. Finally, it prints both arguments. 1 def foo(X = "a", Y = []): X = X + X Y.append(X) print X, Y When she called foo() with no arguments repeatedly, she was surprised and puzzled by the results: 2 به بیا . 3 4 >>> for i in range (4): foo() aa ['aa'] aa ['aa', 'aa'] aa ['aa', 'aa', 'aa'] aa ['aa', 'aa', 'aa', 'aa'] Explain to your classmate what is going on in this Python example and if the results are expected.
Your classmate wrote a simple function with two optional arguments: X which defaults to the string “a” and Y, which defaults to the empty list. It concatenates its first argument to itself and then appends that to the end of its second argument. Finally, it prints both arguments. 1 def foo(X = "a", Y = []): X = X + X Y.append(X) print X, Y When she called foo() with no arguments repeatedly, she was surprised and puzzled by the results: 2 به بیا . 3 4 >>> for i in range (4): foo() aa ['aa'] aa ['aa', 'aa'] aa ['aa', 'aa', 'aa'] aa ['aa', 'aa', 'aa', 'aa'] Explain to your classmate what is going on in this Python example and if the results are expected.
Chapter8: Arrays
Section: Chapter Questions
Problem 5PE
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Can someone please explain to me ASAP??!!!!
![Your classmate wrote a simple function with two optional arguments: X which defaults to the string "a" and
Y, which defaults to the empty list. It concatenates its first argument to itself and then appends that to the end
of its second argument. Finally, it prints both arguments.
1
2
def foo(X = "a", Y = []):
X = X + X
Y.append(X)
print X, Y
4
When she called foo() with no arguments repeatedly, she was surprised and puzzled by the results:
>>> for i in range (4): foo()
aa ['aa']
aa ['aa', 'aa']
aa ['aa', 'aa', 'aa']
aa ['aa', 'aa', 'aa', 'aa']
Explain to your classmate what is going on in this Python example and if the results are expected.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F11ad9986-04b0-4336-8340-a3038312afe8%2F399af39f-4dd7-4f96-bc16-ecd0b968612b%2Fdvys44i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Your classmate wrote a simple function with two optional arguments: X which defaults to the string "a" and
Y, which defaults to the empty list. It concatenates its first argument to itself and then appends that to the end
of its second argument. Finally, it prints both arguments.
1
2
def foo(X = "a", Y = []):
X = X + X
Y.append(X)
print X, Y
4
When she called foo() with no arguments repeatedly, she was surprised and puzzled by the results:
>>> for i in range (4): foo()
aa ['aa']
aa ['aa', 'aa']
aa ['aa', 'aa', 'aa']
aa ['aa', 'aa', 'aa', 'aa']
Explain to your classmate what is going on in this Python example and if the results are expected.
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