Your answer is partially correct. There were 49.7 million people with some type of long-lasting condition or disability living in the United States in 2000. This represented 19.3 percent of the majority of civilians aged five and over (http://factfinder.census.gov). A sample of 1000 persons is selected at random. Use normal approximation. Round the answers to four decimal places (e.g. 98.7654). (a) Approximate the probability that more than 208 persons in the sample have a disability. 0.1075 (b) Approximate the probability that between 180 and 300 people in the sample have a disability. i 0.8599 Statistical Tables and Charts
Your answer is partially correct. There were 49.7 million people with some type of long-lasting condition or disability living in the United States in 2000. This represented 19.3 percent of the majority of civilians aged five and over (http://factfinder.census.gov). A sample of 1000 persons is selected at random. Use normal approximation. Round the answers to four decimal places (e.g. 98.7654). (a) Approximate the probability that more than 208 persons in the sample have a disability. 0.1075 (b) Approximate the probability that between 180 and 300 people in the sample have a disability. i 0.8599 Statistical Tables and Charts
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Your answer is partially correct.
There were 49.7 million people with some type of long-lasting condition or disability living in the United States in 2000. This
represented 19.3 percent of the majority of civilians aged five and over (http://factfinder.census.gov). A sample of 1000 persons is
selected at random.
Use normal approximation. Round the answers to four decimal places (e.g. 98.7654).
(a) Approximate the probability that more than 208 persons in the sample have a disability.
0.1075
(b) Approximate the probability that between 180 and 300 people in the sample have a disability.
0.8599
i
Statistical Tables and Charts
Expert Solution
Step 1
Given, here used by binomial approximation.
P = 19.3% = 0.193 sample is 1000
We wil change into normal approximation then solve.
Step by step
Solved in 4 steps with 3 images
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