You would think that your blood alcohol content (BAC) would be directly proportional to how many beers you drink in an hour. Strangely enough, for both males and females of a specific weight, the BAC is directly proportional to the number (N − 1) of beers they drank during the last hour. (a) Write an equation of variation between BAC and the number of beers a man drank during the last hour. (Use k as the constant of variation.) BAC =  k(N−1)       (b) For a 150-lb average man, his BAC after 3 beers is 0.046. Find k. (Round your answer to three decimal places.) k =   (c) What is his BAC after 5 beers? (Round your answer to three decimal places.) (d) How many beers can the man drink before going over the 0.08 BAC limit? (Round your answer to the nearest whole number.)  __________ beers

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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You would think that your blood alcohol content (BAC) would be directly proportional to how many beers you drink in an hour. Strangely enough, for both males and females of a specific weight, the BAC is directly proportional to the number (N − 1) of beers they drank during the last hour.

(a) Write an equation of variation between BAC and the number of beers a man drank during the last hour. (Use k as the constant of variation.)
BAC =  k(N−1)
 
 
 

(b) For a 150-lb average man, his BAC after 3 beers is 0.046. Find k. (Round your answer to three decimal places.)
k =  

(c) What is his BAC after 5 beers? (Round your answer to three decimal places.)


(d) How many beers can the man drink before going over the 0.08 BAC limit? (Round your answer to the nearest whole number.)
 __________ beers
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