You work for a consumer watchdog publication and are testing the advertising claims of a tire manufacturer. The manufacturer dlaims that the life spans of the tires are normally distributed, with a mean of 40.000 miles and a standard deviation of5500 miles. You test 16 tires and get the following life spans. Complete parts (a) through (c) below.48,945 42,213 24,051 36,117 32,209 41,001 42,888 37,719 D23,231 29,347 34,274 36,641 30,122 36,334 33,621 44,904O B.Oc.Life spans of tiresLife spans of tiresLife spans of tires25 0225 80046.17446,37425246374Distance (in miles)Distance (in miles)Distance (in miles)Is it reasonableassume that the life spans are normally distributed? Why? Choose the correct answer below.O A. No, because the histogram is neither symmetric nor bell-shaped.OB. Yes, because the histogram is neither symmetric nor bell-shaped.c. Yes, because the histogram is symmetric and bell-shaped.O D. No, because the histogram is symmetric and bell-shaped.(b) Find the mean of your sample.The mean is 35851.1. (Round to one decimal place as needed.)Find the standard deviation of your sample.The standard deviation is (Round to one decimal place as needed.)

Answered: Image /qna-images/answer/3239050c-f697-4e13-a04c-adaba421dcd5.jpg

Answered: You work for a consumer watchdog…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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ANSWER ASAP FInd the following: mean, median, mode, variance, and standard deviation.
You work for a consumer watchdog publication and are testing the advertising claims of a tire manufacturer. The manufacturer claims that the life spans of the tires are normally distributed, with a mean of 40,000 miles and a standard deviation of 4500 miles. You test 16 tires and get the following life spans. Complete parts (a) through (c) below. 48,250, 43,242, 27,538, 38,187, 30,583, 40,298, 40,623, 35,366, 24,131, 33,680, 38,592, 36,796, 32,216, 37,370, 36,319, 47,459 Draw a frequency histogram to display these data. Use five classes. Then choose the from a, b, or c, for the correct answer below.
Calculate the mean, median and sample standard deviation for the following data. 1, 5, 2, 6, 8
You work for a consumer watchdog publication and are testing the advertising claims of a tire manufacturer. The manufacturer claims that the life spans of the tires are normally distributed, with a mean of 40,000 miles and a standard deviation of 6500 miles. You test 16 tires and get the following life spans. Complete parts (a) through (c) below. 47,493 39,585 28,756 36,034 30,952 38,287 42,718 34,078 D 24,464 29,573 37,049 36,753 32,401 36,752 34,850 44,188 (a) Draw a frequency histogram to display these data. Use five classes. Choose the correct answer below. OA. OB. Oc. Life spans of tires Life spans of tires. Life spans of tires 45,15 26, 451905 26,75 45,1905 Distance (in miles) Distance (in miles) Distance (in miles) Is it reasonable to assume that the life spans are normally distributed? Why? Choose the correct answer below. O A. No, because the histogram is symmetric and bell-shaped. O B. Yes, because the histogram is neither symmetric nor bell-shaped. O C. Yes, because the…
Compute each of the single-variable statistics discussed in class for the data below: 84.7 58.2 89.1 89.7 44.3 91.9 68.3 84.1 94.9 58.2 Find the mean, median, mode, 1st quartile, 3rd quartile, standard deviation, range, variance.
Kindly also calculate the median, standard deviation and the coefficient of skewness from the data.
I would like you to recheck these questions since there was a mix up with the standard deviation and the mean of the certified. A certified mechanic was timed for the repair of an automobile on 14 separate occasions. Over the same period a trainee mechanic was timed for the repair of a similar automobile. The times in minutes are given below. Certified 344 276 257 334 267 164 222 343 212 175 211 311 209 188 Trainee 222 342 178 234 398 232 377 211 309 190 351 343 177 269 a. Calculate a 99% confidence interval for the mean time taken to repair the automobile by the (i) certified mechanic (ii) the trainee mechanic

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