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- After clicking the Generate Results button, SALT will display the summary of the One Sample t test on the right side of the Inferential Statistics page. Enter the requested values below. Round your standard error to three decimal places and your test statistic to two decimal places. Standard Error: Test Statistic: Degrees of freedom: P-value: 0.493 66.366 53 53 less than 0.05 0.493 66.37 less than 0.05 Step 5 of 5 Since the P-value is less than our significance value of 0.05, this leads us to reject the null hypothesis. Based on the sample data, there ---Select--- convincing evidence that male Boston Marathon winners have an average finish time that is longer than the male Boston Wheelchair Marathon winners than what could have resulted from sampling error alone. In other words, Boston's male wheelchair athlete winners finish a marathon in ---Select--- time, on average, than male Boston marathon winners. Optional extension: In case you would like to investigate whether a similar…Please determine the critical valueUse technology to help you test the claim about the population mean, μ, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: μ> 1270; α=0.02; a=214.81. Sample statistics: x= 1293.27, n=275 Identify the null and alternative hypotheses. Choose the correct answer below. OA. Ho: > 1270 H₂:μ≤ 1270 OB. Ho: 21270 Ha: H1270 C. Ho: H≤ 1270 Ha: H> 1270 OE. Ho: s1293.27 H₂:μ> 1293.27 Calculate the standardized test statistic. The standardized test statistic is 1.80. (Round to two decimal places as needed.) Determine the P-value. P= (Round to three decimal places as needed.) O D. Ho: > 1293.27 Ha: Hs 1293.27 OF. Ho: 21293.27 H₂:1293.27
- Use the following R output to answer the question. Use the following R output to answer the question. >chisq.test(data) Pearsons Chi-square test data:data X-squared=4.7194, df=2, p-value=0.09445 If the significance level is 5%, what conclusion can you make? Group of answer choices A. fail to reject the alternative hypothesis B. cannot determine C. fail to reject the null hypothesis D. reject the null hypothesis and accept the alternative hypothesisUse technology and a t-test to test the claim about the population mean at the given level of significance a using the given sample statistics. Assume the population is normally distributed Claim: u > 78; a = 0.01 Sample statistics: × = 79.3, s = 3.6, n = 28 What are the null and alternative hypotheses? Choose the correct answer below. O A. Ho: M = 78 H: 4*78 О c. Ha: u₴78 Hai n< 78 OB. H: 4478 H: M=78 O D. H: 4 s78 H: 4>78 What is the value of the standardized test statistic? The standardized test statistic is__ . (Round to two decimal places as needed.) What is the P-value of the test statistic? P-value=__(Round to three decimal places as needed.) Decide whether to reject or fail to reject the null hypothesis. Choose the correct answer below.Use technology to help you test the claim about the population mean, μ, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: μ> 1170; x = 0.08; a=207.79. Sample statistics: x= 1198.51, n = 250 Identify the null and alternative hypotheses. Choose the correct answer below. OA. Ho: 21170 H₂H 1198.51 H:Hs 1198.51 Calculate the standardized test statistic. The standardized test statistic is (Round to two decimal places as needed.) Determine the P-value. P= (Round to three decimal places as needed.) Determine the outcome and conclusion of the test. D Ho. At the 8% significance level, there OB. Ho: s1198.51 H: 1198.51 O D. Ho: 1170 H₂: ≤1170 OF. Ho: HS1170 H₂: > 1170 enough evidence to the claim.
- Use technology to help you test the claim about the population mean, μ, at the given level of significance, x, using the given sample statistics. Assume the population is normally distributed. Claim: μ> 1270; α=0.02; a=214.81. Sample statistics: x= 1293.27, n = 275 Identify the null and alternative hypotheses. Choose the correct answer below. OA. Ho: > 1270 OB. Ho: 21270 H₂H1270 H₂H1270 c. Ho: H≤ 1270 H₂: H> 1270 OE. Ho: s1293.27 H₂: > 1293.27 Calculate the standardized test statistic. The standardized test statistic is 1.80. (Round to two decimal places as needed.) Determine the P-value. P= (Round to three decimal places as needed.) OD. Ho: > 1293.27 H₂: Hs 1293.27 OF. Ho: 2 1293.27 H₂: <1293.27You wish to test the following claim (Ha) at a significance level of a = 0.002. Ho: P₁ P2 Ha P₁ P2 : You obtain a sample from the first population with 523 successes and 107 failures. You obtain a sample from the second population with 268 successes and 40 failures. test statistic = p-value [three decimal accuracy] [four decimal accuracy]Use technology to help you test the claim about the population mean, u, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed Claim: 1180; a=0.06: a202.19. Sample statistics x= 1208.77, n=300 Identify the null and alternative hypotheses. Choose the correct answer below. OA H 1208.77 H1208.77 OC. H₂>1208.77 H:Hs 1208.77 OE H:1208.77 H₂>1208.77 Calculate the standardized test statistic The standardized test statistic in (Round to two decimal places as needed) Determine the P-value P= (Round to three decimal places as needed.) Determine the outcome and conclusion of the test Ho. At the 6% significance level, there enough evidence to OB. Hop21180 H₂1180 OD. Hus 1180 H₂>1180 OF H₂1180 Hps 1180 the claim