You wish to test the following claim (H.) at a significance level of a = 0.02. H¸:µ = 62.8 Ha:µ # 62.8 You believe the population is normally distributed and you know the standard deviation is o = 13.4. You obtain a sample mean of M = 61 for a sample of size n = 44.

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You wish to test the following claim (H.) at a
significance level of a = 0.02.
H.:µ = 62.8
Ha:µ # 62.8
You believe the population is normally distributed
and you know the standard deviation is o =
13.4.
You obtain a sample mean of M = 61 for a sample
of size n
44.
What is the test statistic for this sample? (Report
answer accurate to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer
accurate to four decimal places.)
p-value =
The p-value is...
less than (or equal to) a
greater than a
Transcribed Image Text:You wish to test the following claim (H.) at a significance level of a = 0.02. H.:µ = 62.8 Ha:µ # 62.8 You believe the population is normally distributed and you know the standard deviation is o = 13.4. You obtain a sample mean of M = 61 for a sample of size n 44. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) a greater than a
Expert Solution
Step 1

The test statistic is,

z=M-μσn=61-62.813.444=-1.82.0201=-0.891

Thus, the test statistic is -0.891.

The hypothesis is two tail. The p-value for two tailed test is,

p-value=Pz<-0.891  or  z>0.891=2×Pz<-0.891

The probability of z less than –0.891 can be obtained using the excel formula “=NORM.S.DIST(–0.891,TRUE)”. The probability value is 0.18647.

The required P-value is,

p-value=2×Pz<-0.891=2×0.18647=0.3729

Thus, the p-value is 0.3729.

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