You wish to prepare 0.53 M KCIO3 from a stock solution of potassium chlorate that is 3.87 M. How many milliliters of the stock solution do you need to make 25.00 mL of 0.53 M KCIO3? Report the volume to 2 sig figs and do not include units in your answer.

You wish to prepare 0.53 M KCIO3 from a stock solution of potassium chlorate that is 3.87 M. How many milliliters of the stock solution do you need to make 25.00 mL of 0.53 M KCIO3? Report the volume to 2 sig figs and do not include units in your answer.

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter3: Molecules, Moles, And Chemical Equations

Section: Chapter Questions

Problem 3.106PAE: 3.106 Twenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What...

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

Question

You wish to prepare 0.53 M KCIO3 from a stock solution of potassium chlorate that is 3.87 M. How
many milliliters of the stock solution do you need to make 25.00 mL of 0.53 M KCIO3? Report the
volume to 2 sig figs and do not include units in your answer.

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