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You wish to find the enthalpy for the reaction 6 Gel, (s) + 14 NHẠI (s) -3 Ge;Hs (1) + 7 N2 (g) + 38 HI (g) Given the following equations Equation 1: 2 Ge (s) + 3 H2 (g) → Ge,H. (1) AH = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) - Gel, (s) + 2 H2(g) AH = -247.8 kJ/mol Equation 3: 2 NH,I (s) - N2 (g) + 2 HI (g) + 3 H2(g) AH = 455.8 kJ/mol In order to place 3 Ge,Hs (1) as products in the desired equation, what do you need to do to the first equation?

You wish to find the enthalpy for the reaction 6 Gel, (s) + 14 NHẠI (s) -3 Ge;Hs (1) + 7 N2 (g) + 38 HI (g) Given the following equations Equation 1: 2 Ge (s) + 3 H2 (g) → Ge,H. (1) AH = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) - Gel, (s) + 2 H2(g) AH = -247.8 kJ/mol Equation 3: 2 NH,I (s) - N2 (g) + 2 HI (g) + 3 H2(g) AH = 455.8 kJ/mol In order to place 3 Ge,Hs (1) as products in the desired equation, what do you need to do to the first equation?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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You wish to find the enthalpy for the reaction 6 Gel, (s) + 14 NHẠI (s) -3 Ge;Hs (1) + 7 N2 (g) + 38 HI (g) Given the following equations Equation 1: 2 Ge (s) + 3 H2 (g) → Ge,H. (1) AH = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) - Gel, (s) + 2 H2(g) AH = -247.8 kJ/mol Equation 3: 2 NH,I (s) - N2 (g) + 2 HI (g) + 3 H2(g) AH = 455.8 kJ/mol In order to place 3 Ge,Hs (1) as products in the desired equation, what do you need to do to the first equation?
Transcribed Image Text:You wish to find the enthalpy for the reaction 6 Gel, (s) + 14 NHẠI (s) -3 Ge;Hs (1) + 7 N2 (g) + 38 HI (g) Given the following equations Equation 1: 2 Ge (s) + 3 H2 (g) → Ge,H. (1) AH = 137.3 kJ/mol Equation 2: Ge (s) + 4 HI (g) - Gel, (s) + 2 H2(g) AH = -247.8 kJ/mol Equation 3: 2 NH,I (s) - N2 (g) + 2 HI (g) + 3 H2(g) AH = 455.8 kJ/mol In order to place 3 Ge,Hs (1) as products in the desired equation, what do you need to do to the first equation?
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