You will now do the same for the equation u"" = f(x), subject to the boundary conditions u(0) = u(1) = u'(0) = u'(1) = 0. This equation describes a beam with fixed ends under an external load f (x). (a) Following the procedure described in class (i.e. using the fundamental theorem of calculus and repeated integration by parts), first derive an expression for u"(r), and use it to show that (x - E)2 u'(æ) = ru" (0) +u"(0) + / -f(E) d£. (b) Use part (a) to derive a similar expression for u(x).

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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only a and b

 

1. In class, we derived an integral representation for the solution to the boundary value
problem u" = -f(x), for x E [0, 1], subject to the boundary conditions u(0) = u(1) = 0.
You will now do the same for the equation u" = f(x), subject to the boundary
conditions u(0) = u(1) = u'(0) = u'(1) = 0. This equation describes a beam with fixed
ends under an external load f(x).
(a) Following the procedure described in class (i.e. using the fundamental theorem of
calculus and repeated integration by parts), first derive an expression for u"(x),
and use it to show that
(x – )?
u"(0) + /
-
u'(x) = xu" (0) +
-f(E) d£.
2
(b) Use part (a) to derive a similar expression for u(x).
(c) Use the boundary conditions to show that
u"(0) = e(1 – )*5(€) ag, u"(0)
| (1- €)*(1+25)ƒ(£) d£.
(d) Thus find the Green's function G(x, E), where the solution u has the integral
representation u(x) = S G(x, )f(£) dg. Is it true that G(x, E) = G(£, x)?
Transcribed Image Text:1. In class, we derived an integral representation for the solution to the boundary value problem u" = -f(x), for x E [0, 1], subject to the boundary conditions u(0) = u(1) = 0. You will now do the same for the equation u" = f(x), subject to the boundary conditions u(0) = u(1) = u'(0) = u'(1) = 0. This equation describes a beam with fixed ends under an external load f(x). (a) Following the procedure described in class (i.e. using the fundamental theorem of calculus and repeated integration by parts), first derive an expression for u"(x), and use it to show that (x – )? u"(0) + / - u'(x) = xu" (0) + -f(E) d£. 2 (b) Use part (a) to derive a similar expression for u(x). (c) Use the boundary conditions to show that u"(0) = e(1 – )*5(€) ag, u"(0) | (1- €)*(1+25)ƒ(£) d£. (d) Thus find the Green's function G(x, E), where the solution u has the integral representation u(x) = S G(x, )f(£) dg. Is it true that G(x, E) = G(£, x)?
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