You will build two identical rectangular enclosures next to a each other, sharing a side. You have a total of 408 feet fence to use. Find the dimensions of each pen such that you can enclose the maximum possible area. One approac is to let a represent the length of fencing that the two pens share, and write a formula for the total area of the enclosures. Then find its vertex and interpret it. (Use ft for feet, and ft^2 for square feet.) The length of each pen (along the wall that they share) should be the width should be and the

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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You will build two identical rectangular enclosures next to a each other, sharing a side. You have a total of 408 feet of
fence to use. Find the dimensions of each pen such that you can enclose the maximum possible area. One approach
is to let x represent the length of fencing that the two pens share, and write a formula for the total area of the
enclosures. Then find its vertex and interpret it. (Use ft for feet, and ft^2 for square feet.)
The length of each pen (along the wall that they share) should be
maximum possible area of each pen is
the width should be
and the
Transcribed Image Text:You will build two identical rectangular enclosures next to a each other, sharing a side. You have a total of 408 feet of fence to use. Find the dimensions of each pen such that you can enclose the maximum possible area. One approach is to let x represent the length of fencing that the two pens share, and write a formula for the total area of the enclosures. Then find its vertex and interpret it. (Use ft for feet, and ft^2 for square feet.) The length of each pen (along the wall that they share) should be maximum possible area of each pen is the width should be and the
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