SafariFileEditViewHistoryBookmarksWindowHelpSun 10:15myopenmath.comМyOpenMathb Answered: What is a point estimate for the... | bartlebyb Answered: An engineer wishes to determine the... | bartlebyYou want to obtain a sample to estimate a population proportion. At this point in time, you have noreasonable estimate for the population proportion. You would like to be 95% confident that you esimate iswithin 1.5% of the true population proportion. How large of a sample size is required?Do not round mid-calculation.Submit Question

Name: SafariFileEditViewHistoryBookmarksWindowHelpSun 10:15myopenmath.comМy
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: SafariFileEditViewHistoryBookmarksWindowHelpSun 10:15myopenmath.comМyOpenMathb Answered: What is a point estimate for the... | bartlebyb Answered: An engineer wishes to determine the... | bartlebyYou want to obtain a sample to estimate a population

Answered: You want to obtain a sample to estimate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Topic Video

Question

Safari
File
Edit
View
History
Bookmarks
Window
Help
Sun 10:15
myopenmath.com
МyOpenMath
b Answered: What is a point estimate for the... | bartleby
b Answered: An engineer wishes to determine the... | bartleby
You want to obtain a sample to estimate a population proportion. At this point in time, you have no
reasonable estimate for the population proportion. You would like to be 95% confident that you esimate is
within 1.5% of the true population proportion. How large of a sample size is required?
Do not round mid-calculation.
Submit Question

Expert Solution

Step 1

To obtain a sample to estimate a population proportion.

Given Information:

Confidence Level = 95% = 0.95

Margin of Error = 1.5% = 0.015

Let population proportion ( $p$ ) be 0.50

Sample size (n) can be obtained using the formula:

$n = {(\frac{Z_{α / 2}}{M . E})}^{2} (p \times (1 - p))$

where, $p$ is the population proportion,

$M . E$ is the margin of error

$Z_{α / 2}$ is the z-critical value at significance level $α = \frac{1 - 0.95}{2} = 0.025$

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Hypothesis Tests and Confidence Intervals for Proportions$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions