You want to know whether the pneumonia resistance allele is in Hardy-Weinberg equilibrium in the original wild mouse population in Switzerland from which Black Swiss mice stemmed. You find a population of 200 mice on a Swiss mountain top and detect that 72% of them are heterozygous carriers of the mutant loss-of-function PNS1 allele and 3% of the mice are completely resistant to pneumonia. Here is a Chi square table for reference: Degrees of Freedom P = 0.99 0.95 0.80 0.50 0.20 0.05 0.01 1. 0.000157 0.00393 0.0642 0.455 1.642 3.841 6.635 2. 0.020 0.103 0.446 1.386 3.219 5.991 9.210 24 3. 0.115 0.352 1.005 2.366 4.642 7.815 11.345 4. 0.297 0.711 1.649 3.357 5.989 9.488 13.277 A. What are the observed and expected values for your Chi-square analysis? (incorrect answers can only receive credit if calculations are clearly shown) B. What is the value you of your Chi-square analysis? (incorrect answers can only receive credit if calculations are clearly shown) C. Is the pneumonia resistance allele is in Hardy-Weinberg equilibrium in the wild mouse population you sampled? Explain your reasoning. D. What agents of change could explain the deviation in allele frequencies between the wild mountain mice and your lab mice. Explain your reasoning.

Human Anatomy & Physiology (11th Edition)
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You want to know whether the pneumonia resistance allele is in Hardy-Weinberg equilibrium in the original wild
mouse population in Switzerland from which Black Swiss mice stemmed. You find a population of 200 mice on a
Swiss mountain top and detect that 72% of them are heterozygous carriers of the mutant loss-of-function PNS1
allele and 3% of the mice are completely resistant to pneumonia.
Here is a Chi square table for reference:
Degrees of Freedom P = 0.99
0.95
0.80
0.50
0.20
0.05
0.01
1.
0.000157
0.00393
0.0642 0.455
1.642
3.841
6.635
2.
0.020
0.103
0.446
1.386
3.219
5.991
9.210
24
3.
0.115
0.352
1.005
2.366
4.642
7.815
11.345
4.
0.297
0.711
1.649
3.357
5.989
9.488
13.277
A. What are the observed and expected values for your Chi-square analysis? (incorrect answers can only receive credit if
calculations are clearly shown)
B. What is the value you of your Chi-square analysis? (incorrect answers can only receive credit if calculations are clearly
shown)
C. Is the pneumonia resistance allele is in Hardy-Weinberg equilibrium in the wild mouse population you sampled?
Explain your reasoning.
D. What agents of change could explain the deviation in allele frequencies between the wild mountain mice and
your lab mice. Explain your reasoning.
Transcribed Image Text:You want to know whether the pneumonia resistance allele is in Hardy-Weinberg equilibrium in the original wild mouse population in Switzerland from which Black Swiss mice stemmed. You find a population of 200 mice on a Swiss mountain top and detect that 72% of them are heterozygous carriers of the mutant loss-of-function PNS1 allele and 3% of the mice are completely resistant to pneumonia. Here is a Chi square table for reference: Degrees of Freedom P = 0.99 0.95 0.80 0.50 0.20 0.05 0.01 1. 0.000157 0.00393 0.0642 0.455 1.642 3.841 6.635 2. 0.020 0.103 0.446 1.386 3.219 5.991 9.210 24 3. 0.115 0.352 1.005 2.366 4.642 7.815 11.345 4. 0.297 0.711 1.649 3.357 5.989 9.488 13.277 A. What are the observed and expected values for your Chi-square analysis? (incorrect answers can only receive credit if calculations are clearly shown) B. What is the value you of your Chi-square analysis? (incorrect answers can only receive credit if calculations are clearly shown) C. Is the pneumonia resistance allele is in Hardy-Weinberg equilibrium in the wild mouse population you sampled? Explain your reasoning. D. What agents of change could explain the deviation in allele frequencies between the wild mountain mice and your lab mice. Explain your reasoning.
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