You try it!! Find the electric field felt on the charge on the bottom-left corner of the square shown below. Each charge is of equal magnitude q = 3E-6 and a= 20ст. 1+q +q [2 a 3 E, E3 45° E
You try it!! Find the electric field felt on the charge on the bottom-left corner of the square shown below. Each charge is of equal magnitude q = 3E-6 and a= 20ст. 1+q +q [2 a 3 E, E3 45° E
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Need to find magnitude and angle of ELECTRIC FIELD on particle on bottom left. Not looking for net force.

Transcribed Image Text:**You try it!!** Find the electric field felt on the charge on the bottom-left corner of the square shown below. Each charge is of equal magnitude \( q = 3 \times 10^{-6} \) and \( a = 20 \text{cm} \).
**Diagram Explanation:**
The diagram illustrates a square with each side marked as 'a'. There are four points on the square labeled 1, 2, 3, and the bottom-left corner which has an unspecified label.
- Point 1 and Point 2 have charges of \( +q \).
- Point 3 and the bottom-left corner have a charge of \( -q \).
The electric field vectors at the bottom-left corner are labeled as \( E_1 \), \( E_2 \), and \( E_3 \).
- \( E_1 \) is directed horizontally to the left.
- \( E_2 \) is directed diagonally to the left at a \( 45^\circ \) angle in relation to the vertical.
- \( E_3 \) is directed vertically downwards.
The diagram provides visual aid for calculating the resultant electric field vector at the bottom-left corner due to the charges located at the other three corners of the square.
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