You throw a ball straight up with an initial velocity of 15.4 m/s. It passes a tree branch on the way up at a height of 6.56 m. How much additional time (in s) will pass before the ball passes the tree branch on th way back down? s

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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You throw a ball straight up with an initial velocity of 15.4 m/s. It passes a tree branch on the way up at a height of 6.56 m. How much additional time (in s) will pass before the ball passes the tree branch on the
way back down?
S
+
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11. [-/0.71 Points]
DETAILS
OSCOLPHYS2016 2.7.P.041.
MY NOTES
PRACTICE ANOTHER
Assume air resistance is negligible unless otherwise stated.
Calculate the displacement and velocity (in m and m/s, respectively) at the following times for a ball thrown straight up with an initial velocity of 19.7 m/s. Take the point of release to be yo = 0.
(a) 0.500 s
Y₁ =
m
=
V₁
m/s
(b) 1.00 s
Y₂ =
m
V₂ =
m/s
(c) 1.50 s
Y3 =
m
V3 =
m/s
(d) 2.00 s
Y4=
m
V4=
m/s
⠀
Transcribed Image Text:[B] WebAssign - Algebra-Based Pix Success Confirmation of Quest x + Homework 2 (1D Kinematics) - X webassign.net/web/Student/Assignment-Responses/submit?dep=29161203&tags=autosave#question3619831_6 C Y 10. [-/0.71 Points] DETAILS OSCOLPHYS2016 2.7.P.049. MY NOTES PRACTICE ANOTHER You throw a ball straight up with an initial velocity of 15.4 m/s. It passes a tree branch on the way up at a height of 6.56 m. How much additional time (in s) will pass before the ball passes the tree branch on the way back down? S + Additional Materials Reading Submit Answer 11. [-/0.71 Points] DETAILS OSCOLPHYS2016 2.7.P.041. MY NOTES PRACTICE ANOTHER Assume air resistance is negligible unless otherwise stated. Calculate the displacement and velocity (in m and m/s, respectively) at the following times for a ball thrown straight up with an initial velocity of 19.7 m/s. Take the point of release to be yo = 0. (a) 0.500 s Y₁ = m = V₁ m/s (b) 1.00 s Y₂ = m V₂ = m/s (c) 1.50 s Y3 = m V3 = m/s (d) 2.00 s Y4= m V4= m/s ⠀
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