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Problem 5 Paintball Slingshot
You stand a distance d from a wall and shoot a paintball towards the wall at an angle above the
horizontal. Suppose the initial velocity of the paintball is vo. (a) At what height does the paintball hit
the wall? (b) Now let 0 = 30°, vo = 20 m s-¹, and d = 10 m. What is the height of the previous part
in meters? (c) For the same values, what is the speed of the ball at the highest point in its trajectory?
What is the speed when it hits the wall?

Expert Solution

Step 1

Given that,

the initial velocity is $v_{o}$

shoot angle from horizontal is $θ$

target distance is $x = d$

Since this is a projectile motion, acceleration is only due to gravity which is only in a downward direction.

The horizontal component of initial velocity is $v_{x} = v_{o} \cos θ$

And the vertical component of initial velocity is $v_{y} = v_{o} \sin θ$

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