You should be able to do this in your head. Hint: This is a rotation matrix. [cos(0) sin(0) [sin(0) cos(0) - 0] -1 cos (0) x -sin (0) sin (0) x cos (0) x

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
You should be able to do this in your head.
Hint: This is a rotation matrix.
[cos(6)
[sin (0)
- sin(
cos(0)
cos (0) x
-sin (0)
sin (0) x
cos (0) X
Transcribed Image Text:You should be able to do this in your head. Hint: This is a rotation matrix. [cos(6) [sin (0) - sin( cos(0) cos (0) x -sin (0) sin (0) x cos (0) X
Expert Solution
Step 1: Given:

A equals open square brackets table row cell cos open parentheses theta close parentheses end cell cell negative sin open parentheses theta close parentheses end cell row cell sin open parentheses theta close parentheses end cell cell cos open parentheses theta close parentheses end cell end table close square brackets

We have to find A to the power of negative 1 end exponent.

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