You shoot a bullet aiming to a far away tree. The bullet is 15.0 g and it embedded 15.0 cm into the trunk of a tree. If the speed of the bullet just before entering the tree is 120.0 m/s, a) How much work is done by the average force? b) what is the average force exerted on the bullet by the tree? c) What is the average acceleration of the bullet in the tree?

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You shoot a bullet aiming to a far away tree. The bullet is 15.0 g and it embedded 15.0 cm into the trunk of a tree. If the speed of the bullet just before entering the tree is 120.0 m/s,
a) How much work is done by the average force?
b) what is the average force exerted on the bullet by the tree?
c) What is the average acceleration of the bullet in the tree?

Expert Solution
Step 1

a)

The work done is change in kinetic energy.

therefore,

W=12mv2-12mu2  W=1215.0×10-3 kg0 m/s2-1215.0×10-3 g120.0 m/s2W=-108 J

b)

The average force is,

W=FavdFav=Wd=-108 J15.0×10-2 m=-720 N

 

The negative sign indicate that the force is against the motion of the bullet.

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