You roll a die 36 times. The table shows the results. For which number is the experimental pro probability? Rolling a Die One Two Three Four Five Six 4 6. 4. One Two O Three 8. 9
You roll a die 36 times. The table shows the results. For which number is the experimental pro probability? Rolling a Die One Two Three Four Five Six 4 6. 4. One Two O Three 8. 9
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![**Rolling a Die Experiment**
**Question:**
You roll a die 36 times. The table shows the results. For which number is the experimental probability of rolling the number the same as the theoretical probability?
**Table:**
| Number on the Die | Frequency of Rolls |
|-------------------|-------------------|
| One | 4 |
| Two | 6 |
| Three | 9 |
| Four | 5 |
| Five | 4 |
| Six | 8 |
**Options:**
- [ ] One
- [ ] Two
- [ ] Three
- [x] Four
- [ ] Five
- [ ] Six
**Explanation:**
The theoretical probability of rolling any particular number on a fair six-sided die is \( \frac{1}{6} \). To find the experimental probability, we divide the frequency of each outcome by the total number of rolls, which is 36.
Let's calculate the experimental probabilities:
- For the number one: \( \frac{4}{36} = \frac{1}{9} \)
- For the number two: \( \frac{6}{36} = \frac{1}{6} \)
- For the number three: \( \frac{9}{36} = \frac{1}{4} \)
- For the number four: \( \frac{5}{36} \) (this does not simplify to \( \frac{1}{6} \))
- For the number five: \( \frac{4}{36} = \frac{1}{9} \)
- For the number six: \( \frac{8}{36} = \frac{2}{9} \)
From the calculations above, the experimental probability that matches the theoretical probability (which is \( \frac{1}{6} \)) is for the number two.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24eefc23-0e75-424c-a7eb-5a4c78dc2fd3%2Fb3db6663-ff81-4076-a06a-2b481e28bdc6%2F0cd3ifg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Rolling a Die Experiment**
**Question:**
You roll a die 36 times. The table shows the results. For which number is the experimental probability of rolling the number the same as the theoretical probability?
**Table:**
| Number on the Die | Frequency of Rolls |
|-------------------|-------------------|
| One | 4 |
| Two | 6 |
| Three | 9 |
| Four | 5 |
| Five | 4 |
| Six | 8 |
**Options:**
- [ ] One
- [ ] Two
- [ ] Three
- [x] Four
- [ ] Five
- [ ] Six
**Explanation:**
The theoretical probability of rolling any particular number on a fair six-sided die is \( \frac{1}{6} \). To find the experimental probability, we divide the frequency of each outcome by the total number of rolls, which is 36.
Let's calculate the experimental probabilities:
- For the number one: \( \frac{4}{36} = \frac{1}{9} \)
- For the number two: \( \frac{6}{36} = \frac{1}{6} \)
- For the number three: \( \frac{9}{36} = \frac{1}{4} \)
- For the number four: \( \frac{5}{36} \) (this does not simplify to \( \frac{1}{6} \))
- For the number five: \( \frac{4}{36} = \frac{1}{9} \)
- For the number six: \( \frac{8}{36} = \frac{2}{9} \)
From the calculations above, the experimental probability that matches the theoretical probability (which is \( \frac{1}{6} \)) is for the number two.
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