You read an article in Golf Digest that someone with your average drive distance will have an average score of 84.71. You keep track of your scores for the next 10 rounds and see that your average score is 76.81 with a standard deviation of 2.939 strokes. You create a 90% confidence interval for your average score and it is (75.11, 78.51). Given this information, what is the best conclusion?   Question 9 options:   1)  The percentage of rounds in which you score more than 84.71 is 90%.   2)  We cannot determine the proper interpretation based on the information given.   3)  We are 90% confident that your average score is less than 84.71.   4)  The average score does not significantly differ from 84.71.   5)  We are 90% confident that your average score is greater than 84.71.

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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You read an article in Golf Digest that someone with your average drive distance will have an average score of 84.71. You keep track of your scores for the next 10 rounds and see that your average score is 76.81 with a standard deviation of 2.939 strokes. You create a 90% confidence interval for your average score and it is (75.11, 78.51). Given this information, what is the best conclusion?
 

Question 9 options:

 

1) 

The percentage of rounds in which you score more than 84.71 is 90%.
 

2) 

We cannot determine the proper interpretation based on the information given.
 

3) 

We are 90% confident that your average score is less than 84.71.
 

4) 

The average score does not significantly differ from 84.71.
 

5) 

We are 90% confident that your average score is greater than 84.71.
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