You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 91.6 79.7 84.2 77.3 81 66.7 80.4 86 86 Find the 90% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 90% C.I. -

Q: You sample 36 families to find out how much they spent on groceries last month. Your sample mean is…

A: Given data,n=36x=540s=82α=0.05

Q: Using the accompanying Accounting Professionals data to answer the following questions. a. Find and…

A: It is given that the accounting professionals are size 20.

Q: Construct the confidence interval for the population mean mean μ.  c=0.90​, x (x-bar)=16.2​, σ=10.0…

A: The 90% confidence interval for the population mean µ is calculated as follows:

Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: 61 students are asked in a survey how many hours they work during a week. Their responses have a…

A: The random variable X follows normal distribution. The sample size is 61. The sample mean is 24. The…

Q: You draw a simple random sample of 10 items from a Normal Population that has a standard deviation…

A: Computation of critical value: 1-α=0.95α=0.05α2=0.0251-α2=0.975 The critical value of z-distribution…

Q: ool graduates, and ask them their annual incomes. They give you an average income of $35,000 per…

A: As the population standard deviation is known, we will use z distribution. The value of z at 95%…

Q: Mocha Joe has n = 23, a sample average of 1,000,000, and a sample standard deviation of 350,000.…

A:

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Mean()=108.78standard deviation()=10.26sample size(n)=36

Q: You are given the sample mean and the population standard deviation. Use this information to…

A:

Q: a) 10.99 % b) 87.19 7. CJ41.09 ). Il. Eisht pacent of all college graduates hired by companies sley…

A:

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Margin of error (E) for proportion is defined as below                                E = Width2…

Q: The estimated prevalence is 11%, and the desired confidence level is 91% with a margin of error of…

A:

Q: You are given the sample mean and the population standard deviation. Use this information to…

A:

Q: city. Construct a 99% confidence interval estimate of the mean amount of mercury in the population.…

A: From the provided information, Sample size (n) = 7 Confidence level = 99% Level of significance = 1…

Q: A confidence interval was constructed to approximate a population proportion. The interval was from…

A: We have given that,  Let p̂ represents the sample proportion and E represents the margin of error,…

Q: Which of the following confidence intervals would have a wider width for the same set of data? A 90%…

A: We have to find which of the following confidence intervals would have a wider width for the same…

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

Q: Construct the confidence interval for the population mean u.  c​= 0.95, x= 15.7, o= 7.0, and

A: c​= 0.95, x= 15.7, o= 7.0, and n= 90

Q: ou measure 37 textbooks' weights, and find they have a mean weight of 33 ounces. Assume the…

A:

Q: You measure 37 textbooks' weights, and find they have a mean weight of 73 ounces. Assume the…

A: From the provided information, Sample size (n) = 37 Sample mean (x̅) = 73 Population standard…

Q: /hat is the 95% confidence interval for this sample mean? to 82.0 to 67.4 to 82.9 to 67.6

A: As the population standard deviation is known, we will use z distribution. The critical value z at…

Q: Construct the confidence interval for the population mean μ.   c=0.90​, x=16.3​, σ=5.0​, and n=95…

A: Construct the confidence interval for the population mean μ.   c=0.90​, x=16.3​, σ=5.0​, and n=95…

Q: A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a…

A: Given information Sample proportion = 0.36 Sample size (n) = 1100

Q: Part D only

A: From the provided information, The mean and standard deviation of the data can be obtained as:

Q: Sample information: 24 out of 1000 people who were surveyed had type 2 diabetes. Use the above…

A: Given n=1000 x=24

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: From the given information, let X be the price of a certain stock. Total number of business days n =…

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: For the 48 sampled business days (i.e., the sample size, n=48), the sample mean closing price (in $)…

Q: Use the information about each of the following samples to compute the confidence interval to…

A: Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: Find the necessary confidence interval for a population mean ? for the following values. (Round your…

A: sample size(n)=81 Mean(x)=2.63 variance(s2)=0.1017 standard deviation(s)=0.1017 confidence level=95%

Q: Construct the confidence interval for the population mean μ.   c=0.98​, x=7.7​, σ=0.3​, and n= 47…

A:

Q: Construct the confidence interval for the population mean μ.   c=0.98​, x=16.6​, σ=7.0​, and n= 70…

A: Given that  98% confidence interval  x=16.6​, σ=7.0​, and n= 70

Q: ou are given the smaple mean and the population m standard deviation. Use this info to construct the…

A:

Q: you measure the weights of a random sample of twenty-five people. The sample mean is 60 kg. Suppose…

A:

Q: You measure 33 textbooks' weights, and find they have a mean weight of 70 ounces. Assume the…

A:

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: Since we know population standard deviation, Use z-distribution to find z-critical value.…

Q: Tina catches a 14-pound bass.  She does not know the population mean or standard deviation.  So she…

A: From the provided information, The data values are as follow: 9, 12, 13, 10 and 10 Sample size (n) =…