You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 57.5 44.8 65.2 46.5 55.6 53.2 58.3 60 69.5 63.4 67 51.1 Find the 99% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to two decimal places (because the sample data are reported accurate to one decimal place). 99% C.I. =

Q: Find the indicated margin of error. Out of 260 trials, 150 turned out positive. Find the margin of…

A: It is given that the sample size (n) is 260 and the number of positive trials (x) is 150.

Q: A sample of 15 Math SAT scores for women was collected. The mean score for the sample was 472 and…

A:

Q: You sample 36 families to find out how much they spent on groceries last month. Your sample mean is…

A: Given data,n=36x=540s=82α=0.05

Q: d. FIND t a n = 10 for the 90% confidence interval for the mean. %3D

A: d. Given: n=10 α=0.1 The degrees of freedom is obtained as below: df=n-1=10-1=9 Critical value: The…

Q: You want to estimate the mean time college students spend watching online videos each day.  The…

A:

Q: A confidence interval was found to be (2.4, 7.9). What was the point estimate? O A. 5.27 O B. 5.2 O…

A: Given confidence interval is (2.4 , 7.9)Upper limit =7.9Lower limit =2.4

Q: If n = 108, a = 29 and o = 2.6, construct a 91% confidence interval. Give your answers to three…

A: Since we know population standard deviation, use z-distribution to find z-critical value.…

Q: A sample of 16 Math SAT scores for women was collected. The mean score for the sample was 507 and…

A: Sample size n=16 Sample mean x=507 Sample standard deviation s=115 Confidence interval 95% The…

Q: Construct the confidence interval for the populan mean. c = 0.98,x-bar = 4.7,n = 53 a confidence…

A:

Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: 61 students are asked in a survey how many hours they work during a week. Their responses have a…

A: The random variable X follows normal distribution. The sample size is 61. The sample mean is 24. The…

Q: Find the left and right critical values used in the confidence interval for the ratio of the…

A: The level of significance is 0.10 (=1-0.90).

Q: For a sampling distribution of n = 500 and population proportion of 0.48 of those who prefer cookies…

A:

Q: Mocha Joe has n = 23, a sample average of 1,000,000, and a sample standard deviation of 350,000.…

A:

Q: Construct the indicated confidence interval for the population mean . Assume c = 0.98, = 101.3, =…

A:

Q: Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 23.…

A:

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Margin of error (E) for proportion is defined as below                                E = Width2…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given95% confidence interval N=361 x = 59.1 seconds. z= 4.9 SecondsFind the margin of error?

Q: Construct the confidence interval for the population mean y. C= 0.90, x=16.6, o= 10.0, and n= 80

A: Here, C=0.90, x=16.6, σ=10.0, and n=80.

Q: The estimated prevalence is 11%, and the desired confidence level is 91% with a margin of error of…

A:

Q: Construct the confidence interval for the population mean u. c=0.95 x=15.6 and standard deviation =…

A:

Q: Find the 95% interval estimate given the following information: the population standard deviation is…

A: Confidence interval give a range of values for the unknown parameter of the population. The width of…

Q: A confidence interval was constructed to approximate a population proportion. The interval was from…

A: We have given that,  Let p̂ represents the sample proportion and E represents the margin of error,…

Q: If n=240 and X = 192, construct a 90% confidence interval. Enter your answer as an open-interval…

A: 1. The given values are n=240,x=192. The proportion of x is, p^=xn=192240=0.8 Computation of…

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

Q: Construct the confidence interval for the population mean u.  c​= 0.95, x= 15.7, o= 7.0, and

A: c​= 0.95, x= 15.7, o= 7.0, and n= 90

Q: A sample of 17 Math SAT scores for women was collected. The mean score for the sample was 491 and…

A: Given Mean: x¯=491 Standard deviations: s=108 Sample size: n =17 Confidence interval: C.I.=0.95

Q: ou measure 37 textbooks' weights, and find they have a mean weight of 33 ounces. Assume the…

A:

Q: You measure 37 textbooks' weights, and find they have a mean weight of 73 ounces. Assume the…

A: From the provided information, Sample size (n) = 37 Sample mean (x̅) = 73 Population standard…

Q: /hat is the 95% confidence interval for this sample mean? to 82.0 to 67.4 to 82.9 to 67.6

A: As the population standard deviation is known, we will use z distribution. The critical value z at…

Q: You measure 48 textbooks' weights, and find they have a mean weight of 53 ounces. Assume the…

A:

Q: For a sampling distribution of n = 800 and population proportion of 0.42 of those who prefer cookies…

A: We have find distribution...

Q: Construct the confidence interval for the population mean μ.   c=0.90​, x=16.3​, σ=5.0​, and n=95…

A: Construct the confidence interval for the population mean μ.   c=0.90​, x=16.3​, σ=5.0​, and n=95…

Q: A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a…

A: Given information Sample proportion = 0.36 Sample size (n) = 1100

Q: Find the left and right critical values used in the confidence interval for the ratio of the…

A: , 90% level of confidence

Q: A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 66…

A:

Q: Construct the confidence interval for the population mean μ.   c=0.98​, x=7.7​, σ=0.3​, and n= 47…

A:

Q: Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 31.…

A: Given:                         Sample Size (n) = 31                        Confidence Level (c) =…

Q: You measure 31 turtles' weights, and find they have a mean weight of 53 ounces. Assume the…

A:

Q: Construct the confidence interval for the population mean μ.   c=0.98​, x=16.6​, σ=7.0​, and n= 70…

A: Given that  98% confidence interval  x=16.6​, σ=7.0​, and n= 70

Q: Use the Student's t distribution to

A: From the given information, the confidence level is 0.95 Significance level is 1-0.95=0.05 Given…

Q: ou are given the smaple mean and the population m standard deviation. Use this info to construct the…

A: