You measure 28 turtle's weights, and find, they have a mean weight of 51 ounces. Assume the population standard deviation is 6.5 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight. Give your answer as a decimal, to two places +/- ______ ounces.
You measure 28 turtle's weights, and find, they have a mean weight of 51 ounces. Assume the population standard deviation is 6.5 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight. Give your answer as a decimal, to two places +/- ______ ounces.
I need help on figuring out how to input this in the calculator as I know that the mean is 51oz, standard deviation is 6.5 oz, confidence interval is % is 90 and the
To set it up I know I need to find the ounces but how I set it on on a TI-84 calculator. I need to know the steps please. This calculator is confusing. lol. I know that the confidence interval is x (with a line over the top) +/- t o (= standard deviation) /2, n-1 , s/square root n. So the required numbers to fill those in would be 51.0 - ? 6.5/ square root 28, 51.0 + ? 65/ square root 28, I believe anyways. But I do not know to get the missing numbers
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