I need herlp with A,B, and C. I cant figure out how Im getting this wrong. h Hulu | SeriesFigureIXPart AGive the number of total electron groups, the number of bonding groups, and the number of lone pairs for the geometry depicted in (a).Express your answers as integers separated by commas.{ΠΙ ΑΣΦNtotal, Nbonding, Nione =Submit▾ Part BGive the number of total electron groups, the number of bonding groups, and the number of lone pairs for the geometry depicted in (b).Express your answers as integers separated by commas.{ΠΙ ΑΣΦNtotal, Nbonding, Nlone =SubmitPart CRequest AnswerSubmitNtotal, Nbonding, Nlone =Provide FeedbackRequest AnswerWGive the number of total electron groups, the number of bonding groups, and the number of lone pairs for the geometry depicted in (c).Express your answers as integers separated by commas.ΠΙ ΑΣΦ?6Request Answer??63<↓4) ENG010 of 21Review | Constants | Periodic Table>Next >3:03 PM11/12/2022x=(7)

We need to check the possibile geometry from the given shapes. Possible geometries are : Linear, Trigonal planar, tetrahedral, trigonal-bipyramidal, octahedral. Using these geometries different shapes are made by compound as per their bond pairs and lone pairs. In this structure, we are given a perfect octahedral shape which is having 6 bonds. So, we can say that total number of electrons groups are 6. As we can see there are 6 bonds , so total bonding groups are also 6. Lone pair are given as difference between total groups and bonding groups. So, lone pair = 6 - 6 = 0 So, answer is : Ntotal , Nbonding , Nlone = 6, 6, 0 In this structure, we are given a shape called as square planar. This is derived from octahedral geometry which is having 6 electrons groups. So, we can say that total number of electrons groups are 6. As we can see there are only 4 bonds , so total bonding groups are 4. So, lone pair = 6 -4 = 2 So, answer is : Ntotal , Nbonding , Nlone = 6, 4, 2 In this structure, we are given a shape called as see-saw. This is derived from trigonal bipyramidal geometry which have 5 electrons groups. So, we can say that total number of electrons groups are 5. As we can see there are only 4 bonds , so total bonding groups are 4. So, lone pair = 5-4 = 1 So, answer is : Ntotal , Nbonding , Nlone = 5, 4, 1