You may need to use the appropriate technology to answer this question. A sample of 21 items from population 1 has a sample variance s₁² = 5.5 and a sample of 26 items from population 2 has a sample variance s₂² = 2.25. Test the following hypotheses at the 0.05 level of significance. Ho: 0₂²50₂² H₂:0²>0₂² (a) What is your conclusion using the p-value approach? (b) Repeat the test using the critical value approach.

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You may need to use the appropriate technology to answer this question.
A sample of 21 items from population 1 has a sample variance s₁² = 5.5 and a sample of 26 items from population 2
has a sample variance s₂² = 2.25. Test the following hypotheses at the 0.05 level of significance.
Ho:
H₂:₁²
(a) What is your conclusion using the p-value approach?
(b) Repeat the test using the critical value approach.
Step 1
(a) What is your conclusion using the p-value approach?
A hypothesis test comparing two population variances uses the F distribution. The F distribution is not symmetric and its
shape will depend on two values of degrees of freedom, a numerator and denominator degrees of freedom. It is
important to note that the values will never be negative. The F test statistic is calculated as follows where s, ² is the
variance from sample 1, s₂² is the variance from sample 2, and s₁2> s₂². Since the F statistic is calculated using the
larger variance as the numerator, only upper tail areas will be used when finding the p-value.
The size of sample 1 is denoted by n₁ and will have n₁ - 1 degrees of freedom. The size of sample 2 is denoted by n₂
and will have n, - 1 degrees of freedom.
It is given that a sample of 21 items from population 1 has a variance of s,2 = 5.5. A sample of 26 items from
population 2 has a variance of s₂² = 2.25. Use these values to find the F test statistic, rounding the result to two
decimal places.
F =
5.5✔
2.25
2.44✔
5.5
2.44
Step 2
The test statistic was found to be F= 2.44. Before the p-value can be found, the degrees of freedom for the numerator
and denominator must be found.
The sample from population 1 contained 21 items, so n₁ 21
degrees of freedom for the numerator is 0.017303 x.
The sample from population 2 contained 26 items, so n₂ 26
degrees of freedom for the denominator is 25
✓and n₁ - 1 =
and n₂ - 1 =
25
25
X. Thus, the
✓
. Thus, the
Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise You may need to use the appropriate technology to answer this question. A sample of 21 items from population 1 has a sample variance s₁² = 5.5 and a sample of 26 items from population 2 has a sample variance s₂² = 2.25. Test the following hypotheses at the 0.05 level of significance. Ho: H₂:₁² (a) What is your conclusion using the p-value approach? (b) Repeat the test using the critical value approach. Step 1 (a) What is your conclusion using the p-value approach? A hypothesis test comparing two population variances uses the F distribution. The F distribution is not symmetric and its shape will depend on two values of degrees of freedom, a numerator and denominator degrees of freedom. It is important to note that the values will never be negative. The F test statistic is calculated as follows where s, ² is the variance from sample 1, s₂² is the variance from sample 2, and s₁2> s₂². Since the F statistic is calculated using the larger variance as the numerator, only upper tail areas will be used when finding the p-value. The size of sample 1 is denoted by n₁ and will have n₁ - 1 degrees of freedom. The size of sample 2 is denoted by n₂ and will have n, - 1 degrees of freedom. It is given that a sample of 21 items from population 1 has a variance of s,2 = 5.5. A sample of 26 items from population 2 has a variance of s₂² = 2.25. Use these values to find the F test statistic, rounding the result to two decimal places. F = 5.5✔ 2.25 2.44✔ 5.5 2.44 Step 2 The test statistic was found to be F= 2.44. Before the p-value can be found, the degrees of freedom for the numerator and denominator must be found. The sample from population 1 contained 21 items, so n₁ 21 degrees of freedom for the numerator is 0.017303 x. The sample from population 2 contained 26 items, so n₂ 26 degrees of freedom for the denominator is 25 ✓and n₁ - 1 = and n₂ - 1 = 25 25 X. Thus, the ✓ . Thus, the
Expert Solution
Step 1: Providing given information

Sample size of first sample  n1 =21

Sample variance s12=5.5

Sample size of first sample  n2 =26

Sample variance s22=2.25


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