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You may need: Ik = a + 2k-1 2n Evaluate e f₁ (2² (b-a), (2²+5x) dz using the infinite Riemann sum Ar b-a 72 12 Σ(2k-1)= n², =ff(x)dx= = lim Σ f(74) Δε. k-1 k-1 Σ(2k-1)² = (4n²-1) k-1

You may need: Ik = a + 2k-1 2n Evaluate e f₁ (2² (b-a), (2²+5x) dz using the infinite Riemann sum Ar b-a 72 12 Σ(2k-1)= n², =ff(x)dx= = lim Σ f(74) Δε. k-1 k-1 Σ(2k-1)² = (4n²-1) k-1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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You may need: Ik = a + 2k-1 2n Evaluate e f₁ (2² (b-a), (2²+5x) dz using the infinite Riemann sum Ar b-a 72 12 Σ(2k-1)= n², =ff(x)dx= = lim Σ f(74) Δε. k=1 k-1 Σ(2k-1)² = (4n²-1) k-1
Transcribed Image Text:You may need: Ik = a + 2k-1 2n Evaluate e f₁ (2² (b-a), (2²+5x) dz using the infinite Riemann sum Ar b-a 72 12 Σ(2k-1)= n², =ff(x)dx= = lim Σ f(74) Δε. k=1 k-1 Σ(2k-1)² = (4n²-1) k-1
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