You may need: Ik = a + 2k-1 2n Evaluate e f₁ (2² (b-a), (2²+5x) dz using the infinite Riemann sum Ar b-a 72 12 Σ(2k-1)= n², =ff(x)dx= = lim Σ f(74) Δε. k-1 k-1 Σ(2k-1)² = (4n²-1) k-1
You may need: Ik = a + 2k-1 2n Evaluate e f₁ (2² (b-a), (2²+5x) dz using the infinite Riemann sum Ar b-a 72 12 Σ(2k-1)= n², =ff(x)dx= = lim Σ f(74) Δε. k-1 k-1 Σ(2k-1)² = (4n²-1) k-1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![You may need:
Ik = a +
2k-1
2n
Evaluate
e f₁ (2²
(b-a),
(2²+5x) dz using the infinite Riemann sum
Ar
b-a
72
12
Σ(2k-1)= n²,
=ff(x)dx= = lim Σ f(74) Δε.
k=1
k-1
Σ(2k-1)² = (4n²-1)
k-1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ba37d91-3081-42ea-952f-3d2c5579a63d%2Fe7c68a41-13bd-4b62-875d-578a00ca21f1%2Fag719rj_processed.png&w=3840&q=75)
Transcribed Image Text:You may need:
Ik = a +
2k-1
2n
Evaluate
e f₁ (2²
(b-a),
(2²+5x) dz using the infinite Riemann sum
Ar
b-a
72
12
Σ(2k-1)= n²,
=ff(x)dx= = lim Σ f(74) Δε.
k=1
k-1
Σ(2k-1)² = (4n²-1)
k-1
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