Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
You hold an elliptical wire loop in the same two-dimensional x-y plane as a very long wire of constant current in the positive y-direction (as in the image above). The semi-major axis of

You hold an elliptical wire loop in the same two-dimensional x-y plane as a very long wire of constant current in the positive y-direction (as in the image above). The semi-major axis of

icon
Related questions
Question
HINT: For both halves of this problem, make sure to consider the stronger magnetic field closer to the wire.
The current will go around the loop COUNTER-CLOCKWISE, and the magnetic force will pull the loop TOWARDS the wire. (In the positive X direction) The current will go around the loop COUNTER-CLOCKWISE, but there will be NO NET FORCE on the loop due to magnetism. The current will go around the loop CLOCKWISE, but there will be NO NET FORCE on the loop due to magnetism. There will be NO CURRENT through the loop of wire. The current will go around the loop CLOCKWISE, and the magnetic force will pull the loop TOWARDS the wire. (In the positive X direction) The current will go around the loop COUNTER-CLOCKWISE, and the magnetic force will push the loop AWAY FROM the wire. (In the negative X direction) The current will go around the loop CLOCKWISE, and the magnetic force will push the loop AWAY FROM the wire. (In the negative X direction)
Transcribed Image Text:The current will go around the loop COUNTER-CLOCKWISE, and the magnetic force will pull the loop TOWARDS the wire. (In the positive X direction) The current will go around the loop COUNTER-CLOCKWISE, but there will be NO NET FORCE on the loop due to magnetism. The current will go around the loop CLOCKWISE, but there will be NO NET FORCE on the loop due to magnetism. There will be NO CURRENT through the loop of wire. The current will go around the loop CLOCKWISE, and the magnetic force will pull the loop TOWARDS the wire. (In the positive X direction) The current will go around the loop COUNTER-CLOCKWISE, and the magnetic force will push the loop AWAY FROM the wire. (In the negative X direction) The current will go around the loop CLOCKWISE, and the magnetic force will push the loop AWAY FROM the wire. (In the negative X direction)
You hold an elliptical wire loop in the same two-dimensional x-y plane as a very long wire of constant current in the positive y-direction (as in the image above). The semi-major axis of the loop is aligned with the "x- axis" and the semi-minor axis of the loop is aligned with the "y- axis". You then move the loop of wire in the 'negative x-direction' (away from the wire). As you do, what is the direction of current through the loop and the direction of the magnetic force on the loop due to that current?
Transcribed Image Text:You hold an elliptical wire loop in the same two-dimensional x-y plane as a very long wire of constant current in the positive y-direction (as in the image above). The semi-major axis of the loop is aligned with the "x- axis" and the semi-minor axis of the loop is aligned with the "y- axis". You then move the loop of wire in the 'negative x-direction' (away from the wire). As you do, what is the direction of current through the loop and the direction of the magnetic force on the loop due to that current?
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer