You have two threads; f1() and f2(), and two global variables n & m as shown below: int n; int m; void *f1 (void *arg) { int r; } m = 5; = %d\n", r); r = n + m; printf("f1 return NULL; void *f2 (void *arg) { int r; n = 2; = %d\n", r); r = mn; printf("f2 return NULL; } Use Pthread condition variable(s) such that f1 and f2 will print the following output: >./ex2 12=3 fl=7 >./ex2 fl=7 ₤2=3 >./ex2 f2=3 f1 = 7 >./ex2 f2=3 f1 = 7
You have two threads; f1() and f2(), and two global variables n & m as shown below: int n; int m; void *f1 (void *arg) { int r; } m = 5; = %d\n", r); r = n + m; printf("f1 return NULL; void *f2 (void *arg) { int r; n = 2; = %d\n", r); r = mn; printf("f2 return NULL; } Use Pthread condition variable(s) such that f1 and f2 will print the following output: >./ex2 12=3 fl=7 >./ex2 fl=7 ₤2=3 >./ex2 f2=3 f1 = 7 >./ex2 f2=3 f1 = 7
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
what is the solution to this C program problem? I don't understand what the intended output supposed to be
.
![You have two threads; f1() and f2(), and two global variables n & m as shown
below:
int n;
int m;
void *f1 (void *arg)
{
int r;
}
m = 5;
=
%d\n", r);
r = n + m;
printf("f1
return NULL;
void *f2 (void *arg)
{
int r;
n = 2;
= %d\n", r);
r = mn;
printf("f2
return NULL;
}
Use Pthread condition variable(s) such that f1 and f2 will print the following output:
>./ex2
12=3
fl=7
>./ex2
fl=7
₤2=3
>./ex2
f2=3
f1 = 7
>./ex2
f2=3
f1 = 7](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed581cec-09cc-4b69-ad90-0fa5181ba256%2F3f336c5b-6f6c-40ba-973a-a68166ff6120%2Fvtbkmi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You have two threads; f1() and f2(), and two global variables n & m as shown
below:
int n;
int m;
void *f1 (void *arg)
{
int r;
}
m = 5;
=
%d\n", r);
r = n + m;
printf("f1
return NULL;
void *f2 (void *arg)
{
int r;
n = 2;
= %d\n", r);
r = mn;
printf("f2
return NULL;
}
Use Pthread condition variable(s) such that f1 and f2 will print the following output:
>./ex2
12=3
fl=7
>./ex2
fl=7
₤2=3
>./ex2
f2=3
f1 = 7
>./ex2
f2=3
f1 = 7
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