### Calculating the Current for a Solenoid to Achieve Earth's Magnetic FieldYou have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 × 10⁻⁵ T). If your solenoid has 500 turns and is 38 cm long, determine the current you must use in order to obtain a magnetic field of the desired magnitude.**Answer:**28 mA ❌### ExplanationThe problem requires determining the current needed in a solenoid to produce a specific magnetic field. A solenoid is a coil of wire that generates a magnetic field when electric current passes through it. The magnetic field inside a long solenoid is uniform and its magnitude can be calculated using the formula:\[ B = \mu_0 \cdot \left(\frac{N}{L}\right) \cdot I \]Where:- $ B $ is the magnetic field (in Tesla, T).- $ \mu_0 $ is the permeability of free space ($4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}$).- $ N $ is the number of turns in the solenoid.- $ L $ is the length of the solenoid (in meters).- $ I $ is the current (in Amperes, A).To achieve the desired magnetic field, you must adjust the current $ I $ accordingly. This involves rearranging the formula to solve for $ I $. The incorrect answer provided is 28 mA.### Further InsightUnderstanding the physical quantities involved and their relationship helps accurately predict and control magnetic fields in applications related to electromagnetism. Exploring errors in calculation, such as here, supports a deeper comprehension of theoretical and practical aspects.

Magnetic field B = 5× 10-5 T No of turn N = 500, Length L = 38cm L = 0.38 m So,…

You have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 x 10-5 T). If your solenoid has 500 tu current you must use in order to obtain a magnetic field of the desired magnitude. 28 What physical quantities are needed and how are they related in order to obtain the magnetic field of a solenoid? mA

You have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 x 10-5 T). If your solenoid has 500 tu current you must use in order to obtain a magnetic field of the desired magnitude. 28 What physical quantities are needed and how are they related in order to obtain the magnetic field of a solenoid? mA

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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