What is the expected number of progeny in each class assuming independent assortment between the P and L genes? (Your answer should have 1 decimal place.) ### Genetic Analysis of Cat PhenotypesIn this exercise, you have conducted a test cross resulting in four distinct cat phenotypes. The numbers of each phenotype observed are as follows:- 95- 105- 23- 27Unfortunately, the specific phenotypes corresponding to these numbers were not recorded. However, using the provided genetic information, we can deduce the likely associations.#### Genetic Background:- **Gene P**: Controls paw color; P indicates white paws.- **Gene L**: Controls fur length; L indicates short fur.**Objective**: Determine which number corresponds to the phenotype of cats with white paws and short fur (PL gamete).#### Deduction Strategy:1. **Majority Phenotypes (95 and 105)**: These larger numbers likely represent the common phenotypes resulting from dominant traits or a combination that is frequent in the test cross. 2. **Recombinant Phenotypes (23 and 27)**: These smaller numbers likely represent the less common phenotypes, possibly due to recombination events.Based on genetic expectations, the PL gamete (white paws and short fur) typically aligns with one of the majority groups unless evidence indicates otherwise. However, given possible recombination, examine the alignment carefully in the context of known inheritance patterns. In conclusion, evaluate which numbers logically connect to the PL genotype, considering inheritance patterns and frequency of expression.

Name: What is the expected number of progeny in each class assuming indepen
Uploaded: 2024-03-20T06:43:04.000Z
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Description: What is the expected number of progeny in each class assuming independent assortment between the P and L genes? (Your answer should have 1 decimal place.) ### Genetic Analysis of Cat PhenotypesIn this exercise, you have conducted a test cross result

Genes are the hereditary units of life. These are present in the chromosomes. Genes contains two alternative forms known as alleles. The alleles which expresses itself is called dominant allele and which remains suppressed is called recessive allele.Now in the given question it is said that independently assorted. P - dominant p - recessive L - dominant l - recessive P1 - PPLL × ppll F1 PpLl X PpLl Here is the punnette square- P_L_ = 9 P_ll = 3 ppL_ = 3 ppll = 1 Thus the expected frequency of the progeny are: P_L_ = 9/16 = 0.56 P_ll = 3/16 = 0.18 ppL_ = 3/16 = 0.18 ppll = 1/16 = 0.06 2) Now the number of progeny that are white paws with short fur are The highest one that is 105 as the white and short fur are dominant. And this is indicated by the highest ratio that is 9 out of 16. Conclusion Thus from the above explanation, the number of progeny and frequency can be cleared.