Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Q10: what is the correct answer choice
![**Educational Content: Calculating the Number of Glucose Molecules in a Solution**
**Problem Statement:**
You have a freshly prepared 0.1 M solution of glucose in water. Each liter of this solution contains how many glucose molecules?
**Options:**
- \(6.02 \times 10^{22}\)
- \(3.01 \times 10^{23}\)
- \(6.02 \times 10^{24}\)
- \(12.04 \times 10^{23}\)
**Explanation:**
To solve this problem, one must understand the concept of molarity and Avogadro's number. Molarity (M) is defined as the number of moles of solute per liter of solution. Here, a 0.1 M solution of glucose means there are 0.1 moles of glucose in every liter of solution.
Avogadro's number, \(6.02 \times 10^{23}\), is the number of molecules in one mole of any substance. Thus, the number of glucose molecules in 0.1 moles can be calculated by multiplying:
\[
0.1 \, \text{mol} \times 6.02 \times 10^{23} \, \text{molecules/mol} = 6.02 \times 10^{22} \, \text{molecules}
\]
Therefore, the correct answer is \(6.02 \times 10^{22}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F87311036-785b-48b7-ad0a-ffb7f8402d00%2Fcfed271a-d51d-44de-a3a2-b8ea2be19ffa%2Fay51g0p_processed.png&w=3840&q=75)
Transcribed Image Text:**Educational Content: Calculating the Number of Glucose Molecules in a Solution**
**Problem Statement:**
You have a freshly prepared 0.1 M solution of glucose in water. Each liter of this solution contains how many glucose molecules?
**Options:**
- \(6.02 \times 10^{22}\)
- \(3.01 \times 10^{23}\)
- \(6.02 \times 10^{24}\)
- \(12.04 \times 10^{23}\)
**Explanation:**
To solve this problem, one must understand the concept of molarity and Avogadro's number. Molarity (M) is defined as the number of moles of solute per liter of solution. Here, a 0.1 M solution of glucose means there are 0.1 moles of glucose in every liter of solution.
Avogadro's number, \(6.02 \times 10^{23}\), is the number of molecules in one mole of any substance. Thus, the number of glucose molecules in 0.1 moles can be calculated by multiplying:
\[
0.1 \, \text{mol} \times 6.02 \times 10^{23} \, \text{molecules/mol} = 6.02 \times 10^{22} \, \text{molecules}
\]
Therefore, the correct answer is \(6.02 \times 10^{22}\).
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