You have a bag that contains 3 green marbles, 7 red marbles, 3 blue marbles, and 8 black marbles. What is the probability that you will draw a green marble? Edit View Insert Format Tools Table 12pt v Paragraph v BIU T?レ
You have a bag that contains 3 green marbles, 7 red marbles, 3 blue marbles, and 8 black marbles. What is the probability that you will draw a green marble? Edit View Insert Format Tools Table 12pt v Paragraph v BIU T?レ
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![### Question 5
You have a bag that contains 3 green marbles, 7 red marbles, 3 blue marbles, and 8 black marbles.
What is the probability that you will draw a green marble?
**Explanation:**
To find the probability of drawing a green marble, use the formula:
\[ \text{Probability} = \frac{\text{Number of green marbles}}{\text{Total number of marbles}} \]
- Number of green marbles = 3
- Total number of marbles = 3 (green) + 7 (red) + 3 (blue) + 8 (black) = 21
So, the probability is:
\[ \frac{3}{21} = \frac{1}{7} \]
The probability of drawing a green marble is \(\frac{1}{7}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faea0cfeb-d759-4aa5-b2d1-0111d15ac639%2F4fc3d882-d936-49ad-9a77-b19ca5f8321d%2Fp9m3u9c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question 5
You have a bag that contains 3 green marbles, 7 red marbles, 3 blue marbles, and 8 black marbles.
What is the probability that you will draw a green marble?
**Explanation:**
To find the probability of drawing a green marble, use the formula:
\[ \text{Probability} = \frac{\text{Number of green marbles}}{\text{Total number of marbles}} \]
- Number of green marbles = 3
- Total number of marbles = 3 (green) + 7 (red) + 3 (blue) + 8 (black) = 21
So, the probability is:
\[ \frac{3}{21} = \frac{1}{7} \]
The probability of drawing a green marble is \(\frac{1}{7}\).
Expert Solution
Step 1
We have given that
A=Green marble=3
B=Red marble=7
C=Blue marble=3
D=Black marble=8
T=Total number of marble=(3+7+3+8)=21
Step by step
Solved in 2 steps
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